Solve the following two variable Linear equation $A/2+B=0.8$, $7/(A+B/2)=10$

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Solve the following two variable Linear equation $A/2+B=0.8$ , $7/(A+B/2)=10$

Solve the following two variable Linear equation $A/2+B=0.8$ , $7/(A+B/2)=10$

The given pair of equations are:

$A/2+B=0.8⇒A+2B=1.6$ …… (a)

$7/(A+B/2)=10⇒7=10(A+B/2)⇒7=10A+5B$

Let’s, multiply LHS and RHS of equation (a) by $10$ for easy calculation

So, we finally get

$10A+20B=16$ ……………………….. (i) And,

$10A+5B=7$ …………………………… (ii)

Now, subtracting two equations we get,

⇒ $(i)-(ii)$

$15B=9$

⇒ $B=3/5$

Next, putting the value of B in the equation (i) we get,

$A = [16 - 20(3/5)]/10$

⇒ $(16-12)/10=4/10$

∴ $A=2/5$

Thus, the value of A and B obtained are $2/5$ and $3/5$ respectively.

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