**Calculation:**

3 molal solution of NaOH = 3 moles of NaOH dissolved in water

3 mole of NaOH = 120g

Density of solution = 1.110gmL-1

Volume = mass/density

Volume = 1120g/1.110gmL-1

Volume =1.009L

Hence,

Molarity of the solution = 3/1.009

Molarity of the solution = 2.97M