The following distribution represents the height of 160 students of a school.

    \[\begin{tabular}{|l|l|} \hline Height (in cm) & No. of Students \\ \hline $140-145$ & 12 \\ \hline $145-150$ & 20 \\ \hline $150-155$ & 30 \\ \hline $155-160$ & 38 \\ \hline $160-165$ & 24 \\ \hline $165-170$ & 16 \\ \hline $170-175$ & 12 \\ \hline $175-180$ & 8 \\ \hline \end{tabular}\]

Draw an ogive for the given distribution taking 2 \mathrm{~cm}=5 \mathrm{~cm} of height on one axis and 2 \mathrm{~cm}=20 students on the other axis. Using the graph, determine:
(i). The number of students whose height is above 172 \mathrm{~cm}.
The following distribution represents the height of 160 students of a school.

    \[\begin{tabular}{|l|l|} \hline Height (in cm) & No. of Students \\ \hline $140-145$ & 12 \\ \hline $145-150$ & 20 \\ \hline $150-155$ & 30 \\ \hline $155-160$ & 38 \\ \hline $160-165$ & 24 \\ \hline $165-170$ & 16 \\ \hline $170-175$ & 12 \\ \hline $175-180$ & 8 \\ \hline \end{tabular}\]

Draw an ogive for the given distribution taking 2 \mathrm{~cm}=5 \mathrm{~cm} of height on one axis and 2 \mathrm{~cm}=20 students on the other axis. Using the graph, determine:
(i). The number of students whose height is above 172 \mathrm{~cm}.

Solution:

    \[\begin{tabular}{|l|l|l|} \hline \text { Height (in cm) } & \text { No. of Students } & \text { Cumulative frequency } \\ \hline 140-145 & 12 & 12 \\ \hline 145-150 & 20 & 32 \\ \hline 150-155 & 30 & 62 \\ \hline 155-160 & 38 & 100 \\ \hline 160-165 & 24 & 124 \\ \hline 165-170 & 16 & 140 \\ \hline 170-175 & 12 & 152 \\ \hline 175-180 & 8 & 160 \\ \hline & N =160& \\ \hline \end{tabular}\\\]

Let’s now draw an ogive taking height of student along x -axis and cumulative frequency along y -axis.

Selina Solutions Concise Class 10 Maths Chapter 24 ex. 24(E) - 1

(i) Draw a vertical line through mark for 172 on x-axis which meets the curve; then from the curve draw a horizontal line which meets the y-axis at the mark of 145.

So now,

No. of students whose height is above 172 cm

= 160 - 144 = 16