The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms? (i) 4g He (ii) 46g Na (iii) 0.40g Ca (iv) 12g He
The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms? (i) 4g He (ii) 46g Na (iii) 0.40g Ca (iv) 12g He

Correct Answer: (iv) 12g He

Explanation:

The number of atoms present in 4g of Helium – 1 NA

The number of atoms present in 46g of Sodium – 2 NA

The number of atoms present in 0.04g of Calcium – 0.01 NA

The number of atoms present in 12g of Helium – 3 NA

Hence, 12g of Helium contains the greater number of atoms.