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Home » The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is
The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is 0.146 \times{{10}^{-3}} S cm^-1
CBSE | Chemistry | Class 12 | Electrochemistry | NCERT
The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001M KCl solution at 298 K is 0.146 \times{{10}^{-3}} S cm^-1

Solution:

Given,
Conductivity, k =0.146 \times 10^{-3} S cm -1
Resistance, R =1500 \Omega
Concept : We know the formula is,

    \[\text { Cell constant }= k \times R\]

Calculation: Substuting the value of known parameter to evaluate the value of cell constant,
=0.146 \times 10^{-3} \times 1500
=0.219 cm ^{-1}

Final Answer: The cell constant of the cell is =0.219 cm ^{-1}

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