The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 $S cm^–1$. Calculate its molar conductivity.

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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 $S cm^-1$ . Calculate its molar conductivity.

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 $S cm^-1$ . Calculate its molar conductivity.

Solution:

Given, $K =0.0248 S cm ^{-1} C$

$c =0.20 M$

Concept: We know that Molar conductivity, $\Lambda_{m}=\frac{k \times 1000}{c}$

Calculation: Substituting the value of known parameter,

$=\frac{0.0248 \times 1000}{0.2}$

$=124 Scm ^{2} mol ^{-1}$

Final Answer: Thus final answer is, $=124 Scm ^{2} mol ^{-1}$

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