Solution:

When two different dice are thrown, the total number of outcomes = 36.

Let E1 be the event of getting the sum of the numbers on the two dice is 10. These numbers are (4 ,6), (5,5) and (6,4).

Number of favorable outcomes = 3

Therefore, P(getting the sum of the numbers on the two dice is 10) = P(E1) = Number o f outcomes favorable to E /Number o f all possible outcomes =3/ 36 1/12

Thus, the probability of getting the sum of the numbers on the two dice is 10 is – j .