Which of the following cannot exhibit isomerism?
Which of the following cannot exhibit isomerism?

(a) C4H10

(b) C5H12

(c) C3H8

(d) C6H14

Solution:

Option (c) is the answer.

Because there must be greater than or equal to 4 carbon atoms for chain isomerism to occur, propane does not display chain isomerism.

In a molecule like propane, no matter how the carbon atoms are arranged, a new structure cannot be produced, i.e. no matter how the carbon atoms are numbered, the total number of carbons will always be three.

Propane is a three-carbon alkane with the molecular formula C3H8. It is a  gas at standard temperature and pressure.