Answer:
Option (d) is the correct response. When lead nitrate reacts with potassium iodide, a yellow precipitate of lead iodide is formed.
You are given the solution of lead nitrate. In order to obtain a yellow precipitate, you should mix it with a solution of (a) Potassium chloride (b) Potassium nitride(c) Potassium sulphide (d) Potassium iodide
You are given the solution of lead nitrate. In order to obtain a yellow precipitate, you should mix it with a solution of (a) Potassium chloride (b) Potassium nitride(c) Potassium sulphide (d) Potassium iodide