Which term of the A.P. $3,10,17,$ …. will be 84 more than its ${{13}^{th}}$ term ?

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Which term of the A.P. $3,10,17,$ …. will be 84 more than its ${{13}^{th}}$ term ?

An arithmetic progression or arithmetic sequence is a number’s sequence such that the difference between the consecutive terms is constant.

Given A.P. is 3, 10, 17….

Here, a = 3

d = 10 – 3 = 7

Let the term which is 84 more than its 13th term be a_m.

Therefore, it the ${{25}^{th}}$ term which is $84$ more than its ${{13}^{th}}$ term.

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