Some Applications Of Trigonometry

From the top of a building AB, 60 \mathrm{~m} high, the angles of depression of the top and bottom of a vertical lamp post \mathrm{CD} are observed to the 30^{\circ} and 60^{\circ} respectively. Find (iii) the difference between the heights of the building and the lamp post.

$\mathrm{AB}=60 \mathrm{~m}, \angle \mathrm{ACE}=30^{\circ}$ and $\angle \mathrm{ADB}=60^{\circ}$ Let $\mathrm{BD}=\mathrm{CE}=\mathrm{x}$ and $\mathrm{CD}=\mathrm{BE}=\mathrm{y}$ $\Rightarrow...

read more

An electrician has to repair an electric fault on a pole of height 4 meters. He needs to reach a point 1 meter below the top of the pole to undertake the repair work. What should be the length of the ladder that he should use, which when inclined at an angle of 60^{\circ} to the horizontal would enable him to reach the required position?

Let $\mathrm{AC}$ be the pole and $\mathrm{BD}$ be the ladder We have, $\mathrm{AC}=4 \mathrm{~m}, \mathrm{AB}=1 \mathrm{~m}$ and $\angle \mathrm{BDC}=60^{\circ}$ And, $B C=A C-A B=4-1=3 m$ In...

read more

From the top of a vertical tower, the angles depression of two cars in the same straight line with the base of the tower, at an instant are found to be 45^{\circ} and 60^{\circ}. If the cars are 100 \mathrm{~m} apart and are on the same side of the tower, find the height of the tower.

Let OP be the tower and points A and B be the positions of the cars. $\mathrm{AB}=100 \mathrm{~m}, \angle \mathrm{OAP}=60^{\circ} \text { and } \angle \mathrm{OBP}=45^{\circ}$ $\text { Let } O P=h$...

read more

A ladder of length 6meters makes an angle of 45^{\circ} with the floor while leaning against one wall of a room. If the fort of the ladder is kept fixed on the floor and it is made to lean against the opposite wall of the room, it makes an angle of 60^{\circ} with the floor. Find the distance between two walls of the room.

  Let $A B$ and $C D$ be the two opposite walls of the room and the foot of the ladder be fixed at the point $\mathrm{O}$ on the ground. $\mathrm{AO}=\mathrm{CO}=6 \mathrm{~m}, \angle...

read more

As observed form the top of a lighthouse, 100 \mathrm{~m} above sea level, the angle of depression of a ship, sailing directly towards it, changes from 30^{\circ} and 60^{\circ}. Determine the distance travelled by the ship during the period of observation.

Let $\mathrm{OA}$ be the lighthouse and $\mathrm{B}$ and $\mathrm{C}$ be the positions of the ship. $\mathrm{OA}=100 \mathrm{~m}, \angle \mathrm{OBA}=30^{\circ}$ and $\angle \mathrm{OCA}=60^{\circ}$...

read more

The angle of elevation of the top of a tower from ta point on the same level as the foot of the tower is 30^{\circ}. On advancing 150 \mathrm{~m} towards foot of the tower, the angle of elevation becomes 60^{\circ} Show that the height of the tower is 129.9 metres.

Let $A B$ be the tower $\mathrm{CD}=150 \mathrm{~m}, \angle \mathrm{ACB}=30^{\circ}$ and $\angle \mathrm{ADB}=60^{\circ}$ $\mathrm{AB}=\mathrm{h} \mathrm{m}$ and $\mathrm{BD}=\mathrm{x} \mathrm{m}$...

read more

A man on the deck of a ship, 16 \mathrm{~m} above water level, observe that that angle of elevation and depression respectively of the top and bottom of a cliff are 60^{\circ} and 30^{\circ} . Calculate the distance of the cliff from the ship and height of the cliff.

Let $A B$ be the deck of the ship above the water level and $D E$ be the cliff. $\mathrm{AB}=16 \mathrm{~m}$ such that $\mathrm{CD}=16 \mathrm{~m}$ and $\angle \mathrm{BDA}=30^{\circ}$ and $\angle...

read more

The angle of depression form the top of a tower of a point A on the ground is 30^{\circ}. On moving a distance of 20 meters from the point A towards the foot of the tower to a point B, the angle of elevation of the top of the tower to from the point \mathrm{B} is 60^{\circ}. Find the height of the tower and its distance from the point \mathrm{A}.

Let $\mathrm{PQ}$ be the tower. $\mathrm{AB}=20 \mathrm{~m}, \angle \mathrm{PAQ}=30^{\circ}$ and $\angle \mathrm{PBQ}=60^{\circ}$ Let $B Q=x$ and $P Q=h$ In $\triangle \mathrm{PBQ}$, $\tan...

read more

The angle of elevation of the top of a chimney form the foot of a tower is 60^{\circ} and the angle of depression of the foot of the chimney from the top of the tower is 30^{\circ}. If the height of the tower is 40 meters. Find the height of the chimney.

Let $\mathrm{PQ}$ be the chimney and $\mathrm{AB}$ be the tower. $\mathrm{AB}=40 \mathrm{~m}, \angle \mathrm{APB}=30^{\circ}$ and $\angle \mathrm{PAQ}=60^{\circ}$ In $\triangle \mathrm{ABP}$, $\tan...

read more

The horizontal distance between two towers is 60 meters. The angle of depression of the top of the first tower when seen from the top of the second tower is 30^{\circ}. If the height of the second tower is 90 meters. Find the height of the first tower.

Let $\mathrm{DE}$ be the first tower and $\mathrm{AB}$ be the second tower. =>  $\mathrm{AB}=90 \mathrm{~m}$ and $\mathrm{AD}=60 \mathrm{~m}$ such that $\mathrm{CE}=60 \mathrm{~m}$ and $\angle...

read more

The angle of elevation on the top of a building from the foot of a tower is 30^{\circ}. The angle of elevation of the top of the tower when seen from the top of the second water is 60^{\circ}.If the tower is 60 \mathrm{~m} high, find the height of the building.

Let $\mathrm{AB}$ be thee building and $\mathrm{PQ}$ be the tower. $\mathrm{PQ}=60 \mathrm{~m}, \angle \mathrm{APB}=30^{\circ}, \angle \mathrm{PAQ}=60^{\circ}$ In $\triangle \mathrm{APQ}$, $\tan...

read more

A TV tower stands vertically on a bank of canal. Form a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is 60^{\circ}. From another point 20 \mathrm{~m} away from the point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is 30^{\circ}. Find the height of the tower and the width of the canal.

Let $\mathrm{PQ}=\mathrm{h} \mathrm{m}$ be the height of the $\mathrm{TV}$ tower and $\mathrm{BQ}=\mathrm{x} \mathrm{m}$ be the width of the canal. We have, $\mathrm{AB}=20 \mathrm{~m}, \angle...

read more

A straight highway leads to the foot of a tower, A man standing on the top of a the tower observe c car at an angle of depression of 30^{\circ} which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 60^{\circ}. Find the time taken by the car to reach the foot of the tower form this point.

Let $\mathrm{PQ}$ be the tower: $\angle \mathrm{PBQ}=60^{\circ}$ and $\angle \mathrm{PAQ}=30^{\circ}$ Let $P Q=h, A B=x$ and $B Q=y$ In $\triangle \mathrm{APQ}$, $\tan...

read more

Two poles of equal heights are standing opposite to each other on either side of the road which is 80 \mathrm{~m} wide, From a point \mathrm{P} between them on the road, the angle of elevation of the top of one pole is 60^{\circ} and the angle of depression from the top of another pole at P is 30^{\circ}. Find the height of each pole and distance of the point \mathrm{P} from the poles.

Let $A B$ and $C D$ be the equal poles; and BD be the width of the road. $\angle \mathrm{AOB}=60^{\circ}$ and $\angle \mathrm{COD}=60^{\circ}$ In $\triangle \mathrm{AOB}$, $\tan...

read more

On a horizonal plane there is a vertical tower with a flagpole on the top of the tower. At a point, 9 meters away from the foot of the tower, the angle of elevation of the top and bottom of the flagpole are 60^{\circ} and 30^{\circ} respectively. Find the height of the tower and the flagpole mounted on it

Let $\mathrm{OX}$ be the horizontal plane, AD be the tower and $\mathrm{CD}$ be the vertical flagpole We have: $\mathrm{AB}=9 \mathrm{~m}, \angle \mathrm{DBA}=30^{\circ}$ and $\angle...

read more

A statue 1.46 \mathrm{~m} tall, stands on the top of a pedestal. From a point on the ground, the angle of elevation of the top of the status is 60^{\circ} and from the same point, the angle of elevation of the top of the pedestal is 45^{\circ}. Find the height of the pedestal.

Let $\mathrm{AC}$ be the pedestal and $\mathrm{BC}$ be the statue such that $\mathrm{BC}=1.46 \mathrm{~m}$. We have: $\angle \mathrm{ADC}=45^{\circ}$ and $\angle \mathrm{ADB}=60^{\circ}$...

read more

The vertical tower stands on a horizontal plane and is surmounted by a vertical flagstaff of height 6 \mathrm{~m}. At a point on the plane, the angle of elevation of the bottom of the flagstaff is 30^{\circ} and that of the top of the flagstaff 60^{\circ}. Find the height of the tower

Let $\mathrm{AB}$ be the tower and $\mathrm{BC}$ be the flagstaff, $\mathrm{BC}=6 \mathrm{~m}, \angle \mathrm{AOB}=30^{\circ}$ and $\angle \mathrm{AOC}-60^{\circ}$ Let $A B=h$ In $\triangle...

read more

From a point on the ground 40 \mathrm{~m} away from the foot of a tower, the angle of elevation of the top of the tower is 30^{\circ}. The angle of elevation of the top of a water tank (on the top of the tower) is 45^{\circ}, Find (i) the height of the tower, (ii) the depth of the tank.

Let $\mathrm{BC}$ be the tower and $\mathrm{CD}$ be the water tank. $\mathrm{AB}=40 \mathrm{~m}, \angle \mathrm{BAC}=30^{\circ}$ and $\angle \mathrm{BAD}=45^{\circ}$ In $\triangle \mathrm{ABD}$,...

read more

A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of 30°, which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 60°. Find the time taken by the car to reach the foot of the tower from this point.

Solution: Let the tower be AB. The initial position and final position of the car be D and C respectively. Since the man is at the top of the tower, as a result the angles...

read more

A 1.2 m tall girl spots a balloon moving with the wind in a horizontal line at a height of 88.2 m from the ground. The angle of elevation of the balloon from the eyes of the girl at any instant is 60°. After some time, the angle of elevation reduces to 30° (see Fig. 9.13). Find the distance travelled by the balloon during the interval.

Solution: Let the balloon’s initial position be A and final position be B. Balloon’s height above the girl height = 88.2 m – 1.2 m = 87 m. To Calculate: The distance travelled by the balloon = DE =...

read more

As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.

Solution: The lighthouse AB height is 75 m. And let C and D be the positions of the ships. The angles of depression from the lighthouse are 30° and 45° . Draw a figure based on given instructions:...

read more

A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is 60°. From another point 20 m away from this point on the line joing this point to the foot of the tower, the angle of elevation of the top of the tower is 30° (see Fig. 9.12). Find the height of the tower and the width of the canal.

Solution: Provided that, AB is the height of the tower. DC = 20 m (given here) As per figure given, In right angle ΔABD, AB/BD = tan 30° AB/(20+BC) = 1/√3 AB = (20+BC)/√3 … (i) Again, In right angle...

read more

Two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide. From a point between them on the road, the angles of elevation of the top of the poles are 60° and 30°, respectively. Find the height of the poles and the distances of the point from the poles.

Solution: Let AB and CD be poles with equal-height. O is the point between them where the elevation height is measured. The distance between the poles is denoted by BD. AB = CD, as seen in the...

read more

A statue, 1.6 m tall, stands on the top of a pedestal. From a point on the ground, the angle of elevation of the top of the statue is 60° and from the same point the angle of elevation of the top of the pedestal is 45°. Find the height of the pedestal.

Solution: Let AB be the height of statue. The elevation is taken from D, which is a point on the ground. To Calculate: Height of pedestal = BC = AC-AB From the figure above, In right angle ΔBCD,...

read more

A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

Solution: Let the boy to stand initially at point Y with a 30° inclination before approaching the building at point X with a 60° inclination. To Find: XY i.e. the distance walked by the boy...

read more

A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string.

Solution: Draw a figure based on the instructions provided, Let BC be the height of the kite from the ground, i.e., BC = 60 m Inclined length of the string from the ground = AC, and A is the point...

read more

A contractor plans to install two slides for the children to play in a park. For the children below the age of 5 years, she prefers to have a slide whose top is at a height of 1.5 m, and is inclined at an angle of 30° to the ground, whereas for elder children, she wants to have a steep slide at a height of 3m, and inclined at an angle of 60° to the ground. What should be the length of the slide in each case?

Solution: According to the contractor's plan, Let ABC be a 30° inclined slide with length AC, and PQR be a 60° inclined slide with length PR. We need to Find: AC and PR In right angle ΔABC, AB/AC =...

read more

A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.

Solution: Draw a figure based on the given instructions. Let AC be the tree's broken branch. C = 30°  BC = 8 m We need to Find: AB, which is height of the tree, From figure: The sum of AB and...

read more

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30°. (see fig. 9.11)

Solution: The rope is 20 metres long and makes a 30° angle with the ground level. Given here: Measure of AC = 20 m and measure of angle C = 30° We need to Find: Height of the pole Let the...

read more