Let’s assume the digit at unit’s place is a and at ten’s place is b. Thus from the question, the number we need to find is $10b+a$. From the question since the number is $4$ times the sum of the two...

Let’s assume the digit at unit’s place is a and ten’s place is b. Thus from the question, the number we need to find is $10b+a$. From the question since the two digits of the number are differing bb...

Let the two numbers be a and b and assume that a is greater than or equal to b. According to question, we can write the sum of the two numbers as $a+b=1000$ ……….. (i) And the difference between the...

Let’s the digit at unit’s place be a and ten’s place be b. According to question, the two digits of the number are differing by $2$. Thus, we can write $a-b=\pm 2$………….. (i) Now, on reversing the...

Let the digits at unit’s place be a and ten’s place be v, respectively. Thus, the number we need to find is $10b+a$. As per the given question, the sum of the two digit number is $15$. Thus, we...

Let the digit at unit’s place be a and ten’s place be b. Thus, the number to be found is $10b+a$. From given question, the sum of two digit number is equal to $5$. Thus we can write equation...

Let the digit at the unit’s place be a and at ten’s place be b. Then the required number is $10b+a$. According to the given question, The sum of the two digit number is $13$, So, $a+b=13$………… (i) On...

Let’s assume the two numbers to be ‘a’ and ‘b’. Let’s consider that, ‘a’ is greater than or equal to ‘b’. Now, according to the question The sum of the two numbers, $a+b=8$…………. (i) Also, sum is...