, where m is the mass of the gas molecule. Answer: Let ρm represent the number of molecules per unit volume Then the expression for the change in momentum by a molecule on front side is = 2m (v +...
Answer: Volume of the box = 1 m3 = V1 Initial pressure P1 = 1.5 atm Final pressure P2 = 1.4 atm Air pressure Pa = 1 atm Initial temperature T1 = 300 K Final temperature T2 = 300 K Area of the hole =...
Answer: We know that, Time = distance/speed Number of particles per unit volume v = N/volume n = 0.0167 km-3 d = 10 × 10-3 km v = 150 km/hr Therefore, we get: time = 225 hrs
Speed (m/s) % of molecules 200 10 400 20 600 40 800 20 1000 10 a) calculate Vrms and hence T (m = 3.0 × 10-26 kg) b) if all the molecules with speed 1000 m/s escape from the system, calculate new...
a) there is no atmosphere on moon b) there is a fall in temperature with altitude Answer: a) The moon has no atmosphere since the gravitational pull is minimal and the Vrms is bigger on the moon,...
Answer: According to the question, the final KE of the gas is 0 The change in KE is as follows: ∆K= 1/2 (nm)v2 ∆T is the change in the temperature ∆U = nCv∆T ∆K = ∆U Making use of the expression, we...
Answer: According to the question, the volume occupied by the molecules of a gas is 22400 cc and the number of molecules in 1 cc of hydrogen are 2.688 × 1019 We know that the hydrogen has a total...
a) the number of atoms of helium in the balloon b) the total internal energy of the system Answer: We know that the average KE per molecule is 3/2kT No.of moles of helium are n = 5 g mole We have T...
Answer: We have, PV = P(m/ρ) = constant P/ ρ = constant Volume = m/ ρ where m is constant When air is pushed into the cycle's tyre, the mass of the air increases as the number of molecules...
Answer: We know that volume of 1 molecule = 4/3 πr3 = 4.20 × 10-30 m3 And the number of moles in 0.5 g H2 gas = 0.25 mole Volume of H2 molecule in 0.25 mole = 1.04×6.023× 10+23-30 = 6.264 ×...
a) average KE b) rms speeds Answer: a) From the above result, the pressure and temperature are the same, therefore, KEc > KEb > KEa b) When P and T are constant, (Vrms)c > (Vrms)b >...
V1 V2 μ1 μ2 p1 p2 Answer: We know that for an ideal gas, PV = μRT The two equations that we can write are: P1V1 = μ1R1T1 P2V2 = μ2R2T2 P1 = 1 atm, P2 = 2 atm and V1 = 2L, V2 = 3L Also, T1 = T = T2...
Answer: We know that that we can write: I α (1/d2) d1 = 1Å d2 = 2Å Therefore, l1 : l2 = 4 : 1 The ratio of the mean free paths of the molecules is 4:1
Answer: We know that oxygen has 5 degrees of freedom. Therefore, energy per mole = (5/2)RT Therefore, for 2 moles of oxygen, energy = 5RT Neon has 3 degrees of freedom. Therefore, energy per mole...
Answer: Expression for root mean square velocity is as follows: $ {{v}_{rms}}=\sqrt{\frac{v_{1}^{2}+v_{2}^{2}+v_{3}^{2}+......+v_{n}^{2}}{n}} $ For two meolecules, the formula reduces to: $...
Answer: According to the question, Vrms = 100 m/s T1 = 300 K and T2 = 400 K Expression for root mean square velocity is Vrms = √3RT/M Upon substituting the given values, we get Vrms = 115.4...
Answer: According to the question, T1 = 27oC = 300 K and the volume V1 = 100 cm3 It is known that V is proportional to T So, we can write V/T = constant Or, V1/T1 = V2/T2 Upon re-arranging, we have...
Answer: According to the question, the molar mass = mass of Avagadro's number of atoms = 6.023 × 1023 atoms Mass of gold is m = 39.4 g and the molar mass of gold is M = 197 g/mol We know that 197 g...
a) because of collisions with moving parts of the wall only b) because of collisions with the entire wall c) because the molecules gets accelerated in their motion inside the volume d) because of...
Answer: The correct answer is a) c)
a) obeys Maxwell’s distribution b) have the same value for all molecules c) equals the translational kinetic energy for each molecule d) is 2/3rd the translational kinetic energy for each molecule...
a) the total energy per unit volume d) only the translational part of energy because rotational energy is very small compared to the translational energy c) only the translational part of the energy...
a) will be valid b) will not be valid since the ions would experience forces other than due to collision with the walls c) will not be valid since collisions with walls would not be elastic d) will...
a) 1.1 p b) p c) less than p d) between p and 1.1 Answer: The correct option is d) between p and 1.1 Explanation:
a) f1(v) + f2(v) = f(v) obeys the Maxwell’s distribution law b) f1(v), f2(v) will obey the Maxwell’s distribution law separately c) neither f1(v) nor f2(v) will obey the Maxwell’s distribution law...
a) same as the pressure initially b) 2 times the pressure initially c) 10 times the pressure initially d) 20 times the pressure initially Answer: The correct option is d) 20 times the pressure...
a) P1 > P2 b) P1 = P2 c) P1 < P2 d) data is insufficient Answer: The correct option is a) P1 > P2 Explanation: When the pressure of an ideal gas is constant, Chale's law is obeyed, i.e. V ∝...
a) both p and V of the gas will change b) only p will increase according to Charle’s law c) V will change but not p d) p will change but not V Answer: The correct option is c) V will change but not...
a) adiabatic process b) isothermal process c) isobaric process d) isochoric process Answer: The correct option is b) isothermal process Explanation: In an isothermal process, when the temperature...
a) the pressure on EFGH would be zero b) the pressure on all the faces will the equal c) the pressure of EFGH would be double the pressure on ABCD d) the pressure on EFGH would be half that on ABCD...
a) remains the same because 500 m/s is very much smaller than vrms of the gas b) remains the same because the motion of the vessel as a whole does not affect the relative motion of the gas molecules...