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Home » If 22 g of benzene is dissolved in 122 g of carbon tetrachloride, determine the mass percentage of carbon tetrachloride (CCl4) and benzene (C6H6).
If 22 g of benzene is dissolved in 122 g of carbon tetrachloride, determine the mass percentage of carbon tetrachloride (CCl4) and benzene (C6H6).
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If 22 g of benzene is dissolved in 122 g of carbon tetrachloride, determine the mass percentage of carbon tetrachloride (CCl4) and benzene (C6H6).

Benzene’s mass percent

\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)=\frac{\text { Mass of } C_{6} H_{6}}{\text { Total mass of the solution }} v \times 100

=\frac{\text { Mass of } C_{6} H_{6}}{\text { Mass of } C_{6} H_{6}+\text { Mass of } C C l_{4}} \times 100

    \[=\frac{22}{22+122}\times 100\]

    \[=15.28%\]

Carbon Tetrachloride’s mass percent

\left(\mathrm{CCl}_{4}\right)=\frac{\text { Mass of } C C l_{4}}{\text { Total mass of the solution }} \times 100

=\frac{\text{ Mass of }CC{{l}_{4}}}{\text{ Mass of }{{C}_{6}}{{H}_{6}}+\text{ Mass of }CC{{l}_{4}}}\times 100

=\frac{122}{22+122}\times 100

=84.72% .

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