Exercise 28E Archives - Noon Academy

Find the equation of the plane passing through the intersection of the planes x – 2y + z = 1 and 2x + y + z = 8, and parallel to the line with direction ratios 1, 2, 1. Also, find the perpendicular distance of (1, 1, 1) from the plane.

CBSE, Class 12, Exercise 28E, Maths, RS Aggarwal, The Planes

Answer: Cartesian form of equation of plane through the line of intersection of planes: ...

Find the equation of the plane passing through the line of intersection of the planes 2x – y = 0 and 3z – y = 0, and perpendicular to the plane 4x + 5y – 3z = 0.

CBSE, Class 12, Exercise 28E, Maths, RS Aggarwal, The Planes

Answer: Cartesian form of equation of plane through the line of intersection of planes: The equation...

Find the equation of the plane through the line of intersection of the planes x – 3y + z + 6 = 0 and x + 2y + 3z + 5 = 0, and passing through the origin.

CBSE, Class 12, Exercise 28E, Maths, RS Aggarwal, The Planes

Answer: Cartesian form of equation of plane through the line of intersection of planes: - x – 27y – 13z = 0 Multiplying by negative sign, x + 27y + 13z = 0 The equation of the plane is x + 27y + 13z...

Find the equation of the planes passing through the intersection of the planes 2x + 3y – z + 1 = 0 and x + y – 2z + 3 = 0, and perpendicular to the plane 3x – y – 2z – 4 = 0.

CBSE, Class 12, Exercise 28E, The Planes

Answer: Cartesian form of equation of plane through the line of intersection of planes: The equation of the plane is 7x + 13y + 4z = 9.

Find the equation of the plane through the line of intersection of the planes x + y + z = 6 and 2x + 3y + 4z + 5 = 0, and passing through the point (1, 1, 1).

CBSE, Class 12, Exercise 28E, Maths, RS Aggarwal, The Planes

Answer: Cartesian form of equation of plane through the line of intersection of planes: 14x + 14y + 14z – 84 + 6x + 9y + 12z + 15 = 0 20x + 23y + 26z...

Find the equation of the plane passing through each group of points: (i) A (2, 2, -1), B (3, 4, 2) and C (7, 0, 6) (ii) A (0, -1, -1), B (4, 5, 1) and C (3, 9, 4)

CBSE, Class 12, Exercise 28A, Exercise 28B, Exercise 28C, Exercise 28D, Exercise 28E, Exercise 28F, Exercise 28G, Exercise 28H, Maths, RS Aggarwal, The Planes

Answer: (i) Given, A (2, 2, -1) B (3, 4, 2) C (7, 0, 6) ...

Find the equation of the plane passing through the intersection of the planes x – 2y + z = 1 and 2x + y + z = 8, and parallel to the line with direction ratios 1, 2, 1. Also, find the perpendicular distance of (1, 1, 1) from the plane.

Find the equation of the plane passing through the line of intersection of the planes 2x – y = 0 and 3z – y = 0, and perpendicular to the plane 4x + 5y – 3z = 0.

Find the equation of the plane through the line of intersection of the planes x – 3y + z + 6 = 0 and x + 2y + 3z + 5 = 0, and passing through the origin.

Find the equation of the planes passing through the intersection of the planes 2x + 3y – z + 1 = 0 and x + y – 2z + 3 = 0, and perpendicular to the plane 3x – y – 2z – 4 = 0.

Find the equation of the plane through the line of intersection of the planes x + y + z = 6 and 2x + 3y + 4z + 5 = 0, and passing through the point (1, 1, 1).

Find the equation of the plane passing through each group of points: (i) A (2, 2, -1), B (3, 4, 2) and C (7, 0, 6) (ii) A (0, -1, -1), B (4, 5, 1) and C (3, 9, 4)

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