(i) x + y = 5, 2x + 2y = 10
(ii) x – y = 8, 3x – 3y = 16
Arrangements:
(i)
Since
∴The conditions are incidental and they have endless number of potential arrangements.
In this way, the conditions are steady.
For,
![ncert solutions class 10 chapter 3 Ncert solutions class 10 chapter 3-16](https://cdn1.byjus.com/wp-content/uploads/2020/07/ncert-solutions-class-10-chapter-3-16.png)
![ncert solutions class 10 chapter 3 Ncert solutions class 10 chapter 3-17](https://cdn1.byjus.com/wp-content/uploads/2020/07/ncert-solutions-class-10-chapter-3-17.png)
In this way, the conditions are addressed in charts as follows:
![ncert solutions class 10 chapter 3 Ncert solutions class 10 chapter 3-18](https://cdn1.byjus.com/wp-content/uploads/2021/06/NCERT-Solutions-for-Class-10-Maths-Chapter-3-Exercise-3.2-Question-4a.png)
From the figure, we can see, that the lines are covering one another.
Subsequently, the conditions have boundless potential arrangements.
(ii)
Given,
Since,
The conditions are corresponding to one another and have no arrangements. Subsequently, the pair of straight conditions is conflicting.