Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically:
Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically:

(i) x + y = 5, 2x + 2y = 10

(ii) x – y = 8, 3x – 3y = 16

Arrangements:

(i)

    \[x\text{ }+\text{ }y\text{ }=\text{ }5\text{ }and\text{ }2x\text{ }+\text{ }2y\text{ }=\text{ }10\]

 

 

                                                           

    \[\left( a1/a2 \right)\text{ }=\text{ }1/2\]

 

                                                           

    \[\left( b1/b2 \right)\text{ }=\text{ }1/2\]

 

                                                            

    \[\left( c1/c2 \right)\text{ }=\text{ }1/2\]

 

 

Since

               

    \[\left( a1/a2 \right)\text{ }=\text{ }\left( b1/b2 \right)\text{ }=\text{ }\left( c1/c2 \right)\]

 

 

∴The conditions are incidental and they have endless number of potential arrangements.

 

In this way, the conditions are steady.

 

For,

              

    \[x\text{ }+\text{ }y\text{ }=\text{ }5\text{ }or\text{ }x\text{ }=\text{ }5-y\]

 

Ncert solutions class 10 chapter 3-16

    \[2x\text{ }+\text{ }2y\text{ }=\text{ }10\text{ }or\text{ }x\text{ }=\text{ }\left( 10-2y \right)/2\]

  

Ncert solutions class 10 chapter 3-17

In this way, the conditions are addressed in charts as follows:

Ncert solutions class 10 chapter 3-18

From the figure, we can see, that the lines are covering one another.

Subsequently, the conditions have boundless potential arrangements.

(ii)

Given,

                                      

    \[x-y\text{ }=\text{ }8\text{ }and\text{ }3x-3y\text{ }=\text{ }16\]

 

 

                                                           

    \[\left( a1/a2 \right)\text{ }=\text{ }1/3\]

 

                     

    \[\left( b1/b2 \right)\text{ }=\text{ }-\text{ }1/\text{ }-\text{ }3\text{ }=\text{ }1/3\]

 

                                         

    \[\left( c1/c2 \right)\text{ }=\text{ }8/16\text{ }=\text{ }1/2\]

 

 

Since,

             

    \[\left( a1/a2 \right)\text{ }=\text{ }\left( b1/b2 \right)\text{ }\ne \text{ }\left( c1/c2 \right)\]

 

 

The conditions are corresponding to one another and have no arrangements. Subsequently, the pair of straight conditions is conflicting.