Maths

    \[\text { If } A=\left[\begin{array}{cc} 2 & -1 \\ -1 & 2 \end{array}\right], \text { such that } A^{2}-4 A+3 I=0 \text {, then } A^{-1}=\]

(A) \frac{-1}{3}\left[\begin{array}{cc}2 & 1 \\ 1 & 2\end{array}\right] (B) \frac{-1}{3}\left[\begin{array}{cc}2 & -1 \\ -1 & 2\end{array}\right] (C) \frac{1}{3}\left[\begin{array}{cc}-2 & -1 \\ 1 & -2\end{array}\right] (D) \frac{1}{3}\left[\begin{array}{ll}2 & 1 \\ 1 & 2\end{array}\right]

The correct option is option (D) $\therefore \mathrm{A}^{2}=\mathrm{A} \cdot \mathrm{A}=\left[\begin{array}{cc}2 & -1 \\ -1 & 2\end{array}\right] \cdot\left[\begin{array}{cc}2 & -1 \\ -1...

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A teacher on attempting to arrange the students for mass drill in the form of solid square found that 24 students were left. When he increased the size of the square by one student, he found that he was short of 25 students. Find the number of students.

Let there be $x$ rows. Then, the number of students in each row will also be $x$. $\therefore$ Total number of students $=\left(x^{2}+24\right)$ According to the question: $\begin{array}{l}...

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Choose the correct statement. In conductors (A).valence band and conduction band overlap each other. (B) valence band and conduction band are separated by a large energy gap. (C) very small number of electrons are available for electrical conduction. (D) valence band and conduction band are separated by a small energy gap.

CORRECT OPTION IS OPTION (A) Valence and conduction band overlap with each other. Means electrons can easily jump from valence to conduction band. Hence, the conductivity of a conductor is highest...

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In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.
(a) 7x + 5y + 6z + 30 = 0 and 3x – y – 10z + 4 = 0
(b) 2x + y + 3z – 2 = 0 and x – 2y + 5 = 0

Solution: (a) $7 x+5 y+6 z+30=0$ and $3 x-y-10 z+4=0$ It is given that The eq. of the given planes are $7 x+5 y+6 z+30=0$ and $3 x-y-10 z+4=0$ Two planes are $\perp$ if the direction ratio of the...

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A game consists of spinning arrow which comes to rest pointing at one of the numbers

    \[\mathbf{1},\text{ }\mathbf{2},\text{ }\mathbf{3},\text{ }\mathbf{4},\text{ }\mathbf{5},\text{ }\mathbf{6},\text{ }\mathbf{7},\text{ }\mathbf{8},\text{ }\mathbf{9},\text{ }\mathbf{10},\text{ }\mathbf{11},\text{ }\mathbf{12};\]

as shown below. If the outcomes are equally likely, find the probability that the pointer will point at:

    \[\left( \mathbf{v} \right)\]

a number less than or equal to

    \[\mathbf{9}\]

    \[\left( \mathbf{vi} \right)\]

a number between

    \[\mathbf{3}\]

and

    \[\mathbf{11}\]

Solution: \[\left( v \right)\] Favorable outcomes for a number less than or equal to \[9\text{ }are\text{ }1,\text{ }2,\text{ }3,\text{ }4,\text{ }5,\text{ }6,\text{ }7,\text{ }8,\text{ }9\] So,...

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A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number, 1,2,3,….,12 as shown in figure. What is the probability that it will point to:(iii) a number which is multiple of 3? (iv) an even number?

(iii) So, Favorable outcomes i.e. to get a multiple of $3$ are $3,6,9,$ and $12$ Therefore, total number of favorable outcomes i.e. to get a multiple of $3$ is $4$ We know that the Probability =...

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A game consists of spinning arrow which comes to rest pointing at one of the numbers

    \[\mathbf{1},\text{ }\mathbf{2},\text{ }\mathbf{3},\text{ }\mathbf{4},\text{ }\mathbf{5},\text{ }\mathbf{6},\text{ }\mathbf{7},\text{ }\mathbf{8},\text{ }\mathbf{9},\text{ }\mathbf{10},\text{ }\mathbf{11},\text{ }\mathbf{12};\]

as shown below. If the outcomes are equally likely, find the probability that the pointer will point at:

    \[~~~\left( \mathbf{iii} \right)\]

a prime number

    \[\left( \mathbf{iv} \right)\]

a number greater than

    \[\mathbf{8}\]

Solution: \[\left( iii \right)\]Favorable outcomes for a prime number are \[2,\text{ }3,\text{ }5,\text{ }7,\text{ }11\] So, number of favorable outcomes\[~=\text{ }5\] Hence, P(the pointer will be...

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Five cards are given– ten, jack, queen, king, and an ace of diamonds are shuffled face downwards. One card is picked at random. Then (i) What is the probability that the card is a queen? (ii) If a king is drawn first and put aside, then what is the probability that the second card picked up is the (a) ace? (b) king?

Given that Five cards-ten, jack, queen, king and Ace of diamond are shuffled face downwards. to find: Probability of following Total number of cards is $5$ (i) Now Total number of cards which is a...

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A bag contains twenty Rs

    \[\mathbf{5}\]

coins, fifty Rs

    \[\mathbf{2}\]

coins and thirty Re

    \[\mathbf{1}\]

coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin:

    \[\left( \mathbf{iii} \right)\]

will neither be a Rs

    \[\mathbf{5}\]

coin nor be a Re

    \[\mathbf{1}\]

coin?

Solution: \[\left( iii \right)\] Number of favourable outcomes for neither Re \[1\]nor Rs \[5\]coins \[=\] Number of favourable outcomes for Rs\[~2\] coins \[=\text{ }50\text{ }=\text{ }n\left( E...

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A bag contains twenty Rs

    \[\mathbf{5}\]

coins, fifty Rs

    \[\mathbf{2}\]

coins and thirty Re

    \[\mathbf{1}\]

coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin:

    \[\left( \mathbf{i} \right)\]

will be a Re

    \[\mathbf{1}\]

coin?

    \[\left( \mathbf{ii} \right)\]

will not be a Rs

    \[\mathbf{2}\]

coin?

Solution: We have, Total number of coins \[=\text{ }20\text{ }+\text{ }50\text{ }+\text{ }30\text{ }=\text{ }100\] So, the total possible outcomes \[=\text{ }100\text{ }=\text{ }n\left( S \right)\]...

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In a bundle of

    \[\mathbf{50}\]

shirts,

    \[\mathbf{44}\]

are good,

    \[\mathbf{4}\]

have minor defects and

    \[\mathbf{2}\]

have major defects. What is the probability that:

    \[\left( \mathbf{i} \right)\]

it is acceptable to a trader who accepts only a good shirt?

    \[\left( \mathbf{ii} \right)\]

it is acceptable to a trader who rejects only a shirt with major defects?

Solution: We have, Total number of shirts \[=\text{ }50\] Total number of elementary events \[=\text{ }50\text{ }=\text{ }n\left( S \right)\] \[\left( i \right)\] As, trader accepts only good shirts...

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A bag contains

    \[\mathbf{3}\]

red balls,

    \[\mathbf{4}\]

blue balls and

    \[\mathbf{1}\]

yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is:

    \[\left( \mathbf{iii} \right)\]

not yellow

    \[\left( \mathbf{iv} \right)\]

neither yellow nor red

Solution: \[\left( iii \right)\] Probability of not drawing a yellow ball \[=\text{ }1\text{ }\] Probability of drawing a yellow ball Thus, probability of not drawing a yellow ball \[=\text{...

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A bag contains

    \[\mathbf{3}\]

red balls,

    \[\mathbf{4}\]

blue balls and

    \[\mathbf{1}\]

yellow ball, all the balls being identical in shape and size. If a ball is taken out of the bag without looking into it; find the probability that the ball is:

    \[\left( \mathbf{i} \right)\]

yellow

    \[\left( \mathbf{ii} \right)\]

red

Solution: The total number of balls in the bag \[=\text{ }3\text{ }+\text{ }4\text{ }+\text{ }1\text{ }=\text{ }8\] balls So, the number of possible outcomes \[=\text{ }8\text{ }=\text{ }n\left( S...

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multiple Nine cards (identical in all respects) are numbered . A card is selected from them at random. Find the probability that the card selected will be:

    \[\left( \mathbf{iii} \right)\]

an even number and a multiple of

    \[\mathbf{3}\]

    \[\left( \mathbf{iv} \right)\]

an even number or a of

    \[\mathbf{3}\]

Solution: \[\left( iii \right)\] From numbers \[2\text{ }to\text{ }10\], there is one number which is an even number as well as multiple of \[3\text{ }i.e.\text{ }6\] So, favorable number of events...

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p1 and p2 are points on either of the two lines y-√3 and |x|=2 at a distance of 5units from their point of intersection.Find the coordinates of the foot of perpendicular drawn from p1 and p2 on the bisector of theangle between the given lines.

  Since, \[y\text{ }-\text{ }\surd 3\left| x \right|\text{ }=\text{ }2\]If x ≥ 0, then \[y\text{ }-\text{ }\surd 3x\text{ }=\text{ }2\text{ }\ldots ..\text{ }\left( i \right)\] If x < 0,...

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