Answer: Because of the small atomic and ionic sizes of Be and Mg, their electrons are closely attached to the atom. Flames occur as a result of an electron being excited from one of its energy...
ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?Answer: Because an oxygen atom with zero charges contains six electrons, the oxidation state of the atom is zero. An atom of oxygen with a negative charge contains seven electrons, while when it has...
with sodium chloride? Explain.Answer: The Solvay method passes $CO_2$ through a concentrated sodium chloride solution containing ammonia, forming ammonium carbonate and ammonium hydrogen carbonate. Crystals of ammonium hydrogen...
Answer: As a result of their large ionic size and low activation enthalpy, alkali metal compounds create ionic compounds, whereas lithium produces covalent compounds as a result of its small ionic...
Answer: CaSO4, SrSO4, and BaSO4 are insoluble in water, whereas BeSO4 and MgSO4 are readily soluble in water. This is because to the higher hydration enthalpies of the Be2+ and Mg2+ ions, which...
Answer: i) Carbonate thermal stability rises with cationic size. The more stable an alkaline earth metal's oxide, the less stable its carbonate. As BeO is stable, BeCO3 is not. (ii) Alkali metals...
Answer: Beryllium is from Group 2. Unlike the other chemicals, beryllium oxide is amphoteric. Group 2 sulfates are water-soluble, as is $BeSO_4$.
Answer: i) In terms of weight and hardness, lithium and magnesium are both significantly lighter and tougher than the other metals in their respective families. (ii) Both LiCl and MgCl2 halides are...
(ii) 
Answer: (i) Peroxide ions react with water and form $H _{2} O _{2}$. $O _{2}^{2-}+2 H _{2} O \longrightarrow 2 OH ^{-}+ H _{2} O _{2}$ (ii) Superoxides react with water and form $H _{2} O _{2}$...
Answer: The reactivity of alkali metals towards oxygen rises with atomic size. So Li only produces LiO2 (Li2O). Sodium forms mostly sodium peroxide and a little sodium oxide, while potassium forms...
Answer: Lithium has the largest negative E value of any element, measuring β3.04V. Lithium has tiny atomic size and the highest ionization enthalpy of all the elements, although this is offset by...
Solution: Let the linear and angular acceleration be $a$ and $\alpha$ respectively. So, $F β f = Ma$ Where, M = mass of the disc f = force of friction applied at the centre Torque to disc,...
Area of square $=$ area of rectangle $I_{z R}-I_{z S}=m\left(d_{R} / 2\right)^{2}-m\left(d_{S} / 2\right)^{2}$ On solving the above equation, we can get $I_{zR}/I_{zS}>1$
a) $\mathrm{c}^{2}=\mathrm{ab}$ as $\mathrm{l}=\mathrm{mr}^{2}$ $\frac{I_{x R}}{I_{x S}}=\frac{m \frac{b}{2}^{2}}{m \frac{c}{2}^{2}}=\frac{b^{2}}{c^{2}}$ Because $c>b$ we can say, $c^{2}>b^ 2$...
The anticlockwise and clockwise angular velocities of the drum are $\omega_{1}$ and $\omega_{2}$ respectively. When the velocities are equal, there is no force of friction and it is given as...
a) We know, $v_{1} = \omega R$ $v_{2}=\omega^{2}R$ The direction of $v_{1}$ and $v_{2}$ are tangentially upwards in the figure, and they meet at point C. As a result, $f_{12}=-f_{21}$ represents the...
about a horizontal axis. It is placed on a horizontal table. The coefficient of kinetic friction is 
.a) The condition that needs to be satisfied is $v_{cm}=\omega_{o}R$ b) Frictional force is responsible for allowing rolling motion to occur without the disc slipping.
about a horizontal axis. It is placed on a horizontal table. The coefficient of kinetic friction is .a) The linear velocity of the revolving disc changes as it is brought into contact with the table. b) Frictional force is responsible. The figure depicts it:
about a horizontal axis. It is placed on a horizontal table. The coefficient of kinetic friction is .a) Before coming into contact with the table, the disc was rotating, and $v_{cm}=0$ was the rest. b) When the revolving disc comes into contact with the table, the linear velocity of the disc...
and 
about their respective axes and rotating with angular speed 
and 
are brought into contact face to face with their axes of rotation coincident.a) Final kinetic energy = rotational + translation energy $K_{f}=KE_{R}+KE_{T}$ $\Delta \mathrm{K}=-I_{1} l_{2} / 2\left(I_{1}+l_{2}\right)\left(\omega_{1}-\omega_{2}\right) 2<0$ b) Because...
and about their respective axes and rotating with angular speed and are brought into contact face to face with their axes of rotation coincident.a) Because there is no external torque on the system and the gravitational and normal reactions to external forces have net torque zero, the equation of conservation of angular momentum can be...
Solution: Let the mass of the half-disc be M Area of the half-disc will be $\frac{\pi R^{2}}{2}$ Mass per unit area will be $\frac{2M}{\pi R^{2}}$ a) when the disc is half, the centre of mass is (0,...
$r_{c m}=\frac{(n-1) m b+m a}{(n-1) m+m}$ is given Where, ${r_{cm}}$ The position of mass $m$ at the $n^{th}$ vertex is called. $r_{\mathrm{cm}}=0$ $\frac{(n-1) m b+m a}{(n-1) m+m}=0$ $(n-1) m b+m...
Solution: The door's axis is in the y-axis, and it is in the x-y plane. As the force is applied in the z-axis, the door rotates in both the positive and negative directions. Gravity is acting on the...
A wheel is a stiff elastic body with a consistent motion that passes through its center, perpendicular to the wheel's plane. Due to elastic force, every particle of the wheel receives a centripetal...
The torques' vector total equals zero. However, the net force is not zero. The following is the mathematical explanation: $G_{i} \sum_{i=1}^{n} F_{t} \neq 0$ $\tau=\tau_{1}+\tau_{2}+\ldots...
Match the following $\begin{array}{|l|l|} \hline \text { a) } \mathrm{h}=\mathbf{R} / 2 & \text { i) sphere rolls without slipping with a constant velocity and no loss of energy } \\ \hline...
Match the following $\begin{array}{|l|l|} \hline \text { a) } \mathrm{mg} / 4<\mathrm{F}<\mathrm{mg} / 2 & \text { i) cube will move up } \\ \hline \text { b) } \mathrm{F}>\mathrm{mg} /...
We discover that the slope of the $\theta - t $ graph is positive, indicating anticlockwise rotation by convention. As $\theta$ is positive and we also know $\omega = \frac{d\theta}{dt}$ and $tan...
The moment of inertia is related to the square of the distance between the mass and the rotational axis. The distribution of mass in a solid sphere occurs from the sphere's centre to its radius. In...
Correct answers are: b) the moment of inertia of cube about zβ is $I_{z}^{\prime}=I_{z}+\frac{m a^{2}}{2}$ d) $I_{x}=I_{y}$
Correct answers are: b) torque Οβ caused by F about zβ axis is along $-\hat{k}$ c) torque Ο caused by F about the z-axis is greater in magnitude than that about the z-axis
When net external torque on a system of particles about an axis is zero, torque is the cross prodeuct of $\vec r$ and $\vec F = rFsin\theta \times torque=0$ where, $\theta$ is the amgle between the...
and 
are their respective positions vectors drawn from point A which is in the plane of the parallel lines. Choose the correct options:
of particle 1 is about A is 
of particle 2 about A is 
Solution: Correct answers is: d) total angular momentum of the system about A is $l = mv(d_{2}-d_{1})$ Angular momentum of particle 1 about A is given as, $\vec L_1=mvd_1$ Angular momentum of...
and are arranged as shown in the figure. The one carrying I1 is along is the x-axis. The other carrying current I2 is along a line parallel to the y-axis given by x = 0 and z = d. Find the force exerted at O2 because of the wire along the x-axis.F = I(LΓB) = ILB sinΞΈΒ is the magnetic field B on a current-carrying wire. O2Β and I1Β Β are in the βY direction and parallel to the y-axis I2 is perpendicular to the y-axis and parallel to the Y-axis,...
a) Angular momentum L and angular velocity ΟΒ do not have to be parallel for a general rotating motion. c) Momentum p and velocity v are always parallel in a typical translational motion.
where a and b are constant and 0 β€ x β€ 1. The centre of mass of the rod will be at
Correct answer is a) $\frac{3(2+b)}{4(3+b)}$ Considering a differential part of the rod at a distance of $x$, we have, $\begin{array}{l} l=\frac{d m}{d x}=a\left(1+b x^{2}\right) \Rightarrow d...
Correct answer is c) III
Correct answer is b) decreased
Correct answer is d) the angular acceleration is non-zero and remains same.
Solution: Correct answer is b) $2 m v a \hat{e}_{x}$
Solution: Correct answer is c) C
Correct answer is d) a bangle
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Given Area of the square = \[784\] \[c{{m}^{2}}\] Hence Side of the square = \[\sqrt{Area}\] = \[\sqrt{784}\] = \[28\] cm Given that the four circular plates are congruent, Therefore diameter of...
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solution From the given information, it is given that the four circles are placed such that each piece touches the other two pieces. Now by joining the centers of the circles by a line segment, we...
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solution Given Radius of the circle = r = \[5\] cm Given Arc length of the sector = l = \[3.5\] cm Let us consider the central angle (in radians) be \[\theta \]. As we know that Arc length = Radius...
Solution: Given that the three circles are drawn such that each of them touches the other two. Now, by joining the centers of the three circles, We get, Β AB = BC = CA = \[2\] (radius) = \[7\] cm...
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Solution Given AB = \[18\] cm, DC = \[32\] cm Given, Distance between AB and DC = Height = \[14\] cm We know that Β Area of the trapezium = (\[1/2\]) Γ (Sum of parallel sides) Γ Height =...
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Solution: Given Diameter of the circular pond = \[17.5\] m Let us consider r be the radius of the park = \[(17.5/2)\] m = \[8.75\] m Given The circular pond is surrounded by a path of width \[2\] m....
Solution: (i) A group of eleven of the world's best cricket batsmen is not a well-defined collection. Because the criteria used to determine a batsman's talent differ from person to person. As a...
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Solution: From the given information, Radius of the circle = r = \[12\] cm β΄Β OA = OB = \[12\] cm \[\angle AOB={{60}^{\circ }}\] (given) As triangle OAB is an isosceles triangle,Β β΄Β \[\angle...
Solution: From the given information, Radius of the circle = r = \[12\] cm β΄Β OA = OB = \[12\] cm \[\angle AOB={{60}^{\circ }}\] (given) As triangle OAB is an isosceles triangle,Β β΄Β \[\angle...
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Solution From the given question, We got Sides of the triangle are \[15\] m, \[16\] m and \[17\] m. Then, perimeter of the triangle = \[(15+16+17)\] m = \[48\]m Therefore, Semi-perimeter of the...
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solution From the given question, We got, Diameter of front wheels = \[{{d}_{1}}\]= \[80\] cm we got, Diameter of rear wheels = \[{{d}_{2}}\]= \[2\]m = \[200\] cm Let us consider \[{{r}_{1}}\] be...
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From the given question, We got Area of the circular playground = \[22176\] \[{{m}^{2}}\] Let us consider r as the radius of the circle. Therefore, \[\pi {{r}^{2}}=22176\]...
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Solution From the given question, \[AC=6\]cm and \[BC=8\] cm We know that a triangle in a semi-circle with hypotenuse as diameter is right angled triangle. By using Pythagoras theorem in triangle...
Solution: From the given figure, We got that the Length and breadth of the rectangular portion (AFDC) of the flower bed are \[38\] cm and \[10\] cm respectively. We know that, Area of the flower bed...
, where c is the speed of light in vacuum. At the nuclear level, the magnitudes of energy are very small. The energy at nuclear level is usually measured in MeV where 
, the masses are measured in unified equivalent of 1u is 931.5 MeV.a) The energy that is comparable to a given mass can be computed using Einstein's mass-energy relation. $1amu=1u=1.67\times 10^{-27}kg$ On Applying $E=mc^{2}$ we get, E = 931.5 MeV b) As $E=mc^{2}$...
$D_{mars}/D_{earth}=1/2$ Also, $D_{earth}/D_{sun}=1/100$ So, $D_{mars}/D_{sun}=1/2\times 1/100$ At 1AU, the sunβs diameter is = (1/2) degree Therefore, diameter of mars will be = (1/400) degree At...
a) 1 parsec is the distance at which 1 AU long arc subtends an angle of 1s, according to the definition. Using the definition, we can write, 1 parsec = (3600)(180)/Ο AU = 206265 AU = 2 Γ 105 AU b)...
a) 1 mL of oleic acid is found in every 20 mL of oleic acid. This signifies that 1/20 mL of oleic acid is present in each mL of solution. Adding alcohol dilutes 1 mL of this solution to 20 mL. As a...
a) Because oleic acid does not dissolve in water, it is dissolved in alcohol. b) When oleic acid is introduced, lycopodium powder clears the circular area. This makes it possible to measure the area...
Kepler's third law states that, $T^{2} \propto a^{3}$ i.e., square of time period $\left(T^{2}\right)$ of a satellite revolving around a planet, is proportional to the cube of the radius of the...
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Let us consider ABCD be a rectangular field. Given, Length of the field = \[20\] m Given, Breadth of the field = \[16\] m From the given question, A cow is tied with a rope at a point A. Let us...
We will us Principle of homogeneity for solving this problem. $\begin{array}{l} {[\mathrm{h}]=\left[\mathrm{ML}^{2}...
, E, m, l and G denote energy, mass, angular momentum and gravitational constant, respectively. Show that P is a dimensionless quantity.We have, $P=El^{2}m^{-5}G^{-2}$ E is the energy having dimension $ML^{2}T{-2}$ m is the mass having dimension [M] L is the angular momentum having dimension $[ML^{2}T^{1}]$ G is the gravitational...
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From the question Radius of wheel = r = \[35\] cm We know that one revolution of the wheel is equal to Circumference of the wheel i.e., \[2\pi r\] = \[2\times (22/7)\times 35\] = \[220\] cm But,...
. The percentage error in the measurement of a, b, c and d are 1%, 2%, 3% and 4%, respectively. What is the percentage error in quantity X? If the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result.The given physical quantity is $X=a^{2}b^{3}c^{5/2}d^{-2}$ Percentage error in X is given as (βx/x)(100) Percentage error in a is given as (βa/a)(100) = 1% Percentage error in b is given as...
Let Q be the physical quantity as $n_{1}u_{1}=n_{2}u_{2}$ Let $M_{1}$, $L_{1}$, $T_{1}$ be the units of mass, length, and time for the first system. and $M_{2}$,$L_{2}$,$T_{2}$ be the units of mass,...
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We know that Area of a sector of a circle = \[(1/2){{r}^{2}}\theta \], Here Β r is the radius and \[\theta \] is the angle in radians subtended by the arc at the center of the circle From the given...
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Let us take a be the side of square. From the question we got, diagonal of square and diameter of circle is \[8\] cm In right angled triangle ABC, By Using Pythagoras theorem we got,...
$R_{me}=$ distance of the moon from the earth $R_{se}=$ distance of the sun from the moon $A_{sun}=$ area of the sun $A_{moon}=$ area of the moon...
m. Calculate the order of magnitude of time taken by light to reach us from the galaxy.The distance of the galaxy is given as 1025m Speed of light is known as $3\times 10^{8}m/s$ Time taken is t = distance/speed $=3.33\times 10^{16}s$
The ratio of sun-earth diameter is $D_{sun}/D_{earth}=100$
Given Radius of first circle = \[{{r}_{1}}\]Β = \[15\] cm Given Radius of second circle = \[{{r}_{2}}\]Β = \[18\] cm Therefore,Β Circumference of first circle of radius \[{{r}_{1}}\]=Β \[2\pi...
Mass spectrograph is a tool for determining the mass of atoms and molecules.
Because physical quantities differ from location to place, we have several units for the same physical quantity.
Correct answers are a) force/area and b) energy/volume
Correct answers are a) mass of electron b) universal gravitational constant and d) mass of proton
Correct options are b) angular impulse and d) angular momentum
Correct answer is d) $PR-Q^{2}/R$ and e) $(R + Q)/P$
Correct answers are b) y = a sin vt and c) y = a/T sin (t/a)
. When expressed in CGS units of 
, it will be equal to:
Correct answer is c) $1.9\times 10^{12}$ Both Dyne and Newton are force units. While Dyne is measured in the C-G-S (Centimeter β Gram β Second) system, Newton is measured in the contemporary SI...
Correct answer is a) 5.00 mm
Correct answer is a) (0.25 Β± 0.08) m Here, $\mathrm{A}=2.5 \mathrm{~ms}^{-1} \pm 0.5 \mathrm{~ms}^{-1}, \mathrm{~B}=0.10 \mathrm{~s} \pm 0.01 \mathrm{~s}$ $\mathrm{AB}=\left(2.5...
Correct answer is c) Tension and surface tension. Tension has the dimension: $[MLT^-2]$ Surface Tension has the dimension: $[ML^0T^-2]$
Correct answer is a) 164 Β± 3 $cm^{2}$ Error in product of quantities: Suppose $x=a \times b$ Let, $\Delta a$ be the absolute error in measurement of a, $\Delta b$ be the absolute error in...
Correct answer is d) 2.74 and 2.74 By convention, we apply the following criteria for rounding off measurements: 1. If the droppedΒ digit is less than 5, the preceding digit remains unaffected. 2. If...
respectively. The density of the material of the body in correct significant figures is:
Correct answer is c) $1.7g/cm^{3}$
Correct answer is c) 663.8
The correct answer is b) 4 The number of zeroes to the left of a non-zero integer is not considered relevant, whereas the number of zeroes to the right of a non-zero number is.
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The given statement is True Explanation: The distance travelled by a circular wheel of radius r m in one revolution is equal to the circumference of the circle = \[2\pi r\] So we got, Number of...
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The given statement is False Explanation: We know that, Circumference of the circle = \[2\pi d\](d is the diameter of the circle). Thus, the statement is false
The given statement is False Explanation: In major segment, area is not always greater than the are of its corresponding sector In minor segment, area is always greater than the area of its...
Solution: The given statement is False Explanation: From the fig, Let the Diameter of the circle = d Therefore, Diagonal of inner square (EFGH) = Side of the outer square (ABCD) = Diameter of circle...
Answer: The correct answer is option c) C Explanation: Centre of mass represents the mean position of the matter of a system. In the given figure half of the sphere is hollow whereas the second half...
(i) At low pressure as the dark blue curve and the sky blue curve are approaching each other, it shows that the real gas is behaving as an ideal gas at a low pressure. (ii) At high pressure as the...
(i) As the temperature is constant, and the pressure is increasing and the change in the volume is seen as exponentially decreasing. (ii) At constant pressure, by increasing the temperature there is...
As the temperature increases, the intermolecular force operating between the particles decreases, the bond strength increases and also the kinetic energy increases. Hence, as the temperature...
Water has hydrogen bonding that exists as intermolecular force of attraction, hexane has Vander Waal force of attraction existing as intermolecular force of attraction, glycerin also has hydrogen...
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The given statement is true Explanation: Let \[r\] be the radius of circle and is equal \[a\] cm Therefore,Β Diameter of the circle = d = \[2\times Radius\] = \[2a\] cm From the question we got that...
Bubbles have a round surface due to surface tension. A needle can float in water because of the presence of surface tension on the surface of the water.
We know that: Pideal = Preal + an2/V2 Pideal β Preal= an2/V2 Nm-2 = a*mol2/m6 A = Nm4mol-2 The unit of βaβ when the pressure is taken in Nm-2, number of moles in βmolβ and volume in m3 is Nm4mol-2...
(i) The increasing order of βbβ is as follows: He < H2< O2< CO2. As the Vander Waals constant βbβ is approximately equal to the total volume of the molecules of a gas. (ii)The decreasing...
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The given statement is false Explanation: Let Β us assume a be the side of square. From the question we got Β that the circle is inscribed in the square. Therefore, Diameter of circle = Side of square...
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The correct option is (B) \[14:11\] Explanation: Let us take r as the radius of the circle and a as the side of the square. From the given question, Perimeter of a circle of radius r = Perimeter of...
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The correct option is (A) \[{{r}^{2}}\] sq. units Explanation: The largest triangle which can be inscribed in a semi-circle of radius r units is Base of triangle should beΒ equal to the diameter of...
The correction option is (B) Area of the circle > Area of the square Explanation: From Β the given question, Circumference of a circle of radius r Β = Perimeter of a square of side a Let us take Β r...
b) can be zero at specific points c) can be positive or negative d) is bounded
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![\[{{R}_{1}}+{{R}_{2}}=R\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-2e72e6a259b123e5a375df667a83360f_l3.png "Rendered by QuickLaTeX.com")
![\[{{R}_{1}}+{{R}_{2}}>R\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d4a2ccba92d24972d2db45d5265612fb_l3.png "Rendered by QuickLaTeX.com")
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The Correct option(A) \[{{R}_{1}}+{{R}_{2}}=R\] Explanation: From the given question, We got sum of the circumferences of two circles with radiiΒ \[R1\] andΒ \[R2\] is equal to the circumference of a...
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The Correct option is (B) \[R_{1}^{2}+R_{2}^{2}={{R}^{2}}\] Explanation: From the given question, We got sum of the areas of two circles with radiiΒ \[R1\] andΒ \[R2\] is equal to the area of a circle...
CO2 gas cannot be liquefied at a temperature which is greater than its critical temperature i.e 30.98Β°C even by applying any pressure. So as the given temperature is 32Β°C by applying a pressure of...
(i) Compressibility factor, Z is defined as the ratio of the product of pressure and volume to the product of the number of moles, gas constant and temperature. For an ideal gas, the value of Z is...
Under a condition of low pressure and high temperature the assumption made by kinetic theory is true. At high temperature, the molecules will be very far from each other and at low pressure, the...
Hydrogen bonding and dipole-dipole interaction (HF-HF interaction) exists between HF molecule in a liquid state.
Thermal energy arises due to the motion of particles (atoms or molecules) in the body. If we increase the temperature then the kinetic energy of atom and molecule increases significantly and they...
The total pressure of the gas is Pmoist gas = Pdry gas By applying the correction term, we have: Pdry gas = Pmoist gas β Aqueous tension Therefore, the correction term applied to the total pressure...
Hydrogen bonding is stronger in water than in alcohol. So, water has a strong intermolecular attraction than alcohol. The increasing order of surface tension is β Hexane< alcohol< water.
The above statement is true. At a higher temperature the movement of gaseous molecules become faster such that there is no intermolecular attraction. Under this condition, gas behaves like an ideal...
The dimension of the universal gas constant R is energy per degree per mole. In the metre-kilogram-second system, the value of R is 8.3144598 joules per Kelvin per mole. Hence R only depends on the...
The critical temperature is the term used for this phenomenon. Here gas A liquefies means that A is below its critical temperature and gas B does not liquefy on applying high pressure as it is above...
All gases are not ideal gas. This means that they do not follow the above mentioned laws at all conditions of temperature, pressure or volume. Real gas doesnβt obey the gas law at normal temperature...
As it is known, 1 mole of any gas at STP (273K, 1 atm) occupies a 22.4L of volume. So, the molar volume (volume of 1 mole of the gas) of such gases occupy a 22.4L of volume.
Answer: The correct option is d) a bangle. Explanation: The mass of a bangle is distributed along the circumference of the ring shape of the bangle as it is a hollow shape. The center of mass is...
(a) Since the halides are a polar molecule (due to high electronegativity), due to the presence of permanent dipoles, the dipole-dipole interactions along with the London forces are found in HF, HCl...
The factors that determine the states of matter can be determined by two laws: 1) Charle's Law: According to this law, when pressure is kept constant, the volume of an ideal gas (V) is directly...
(a) CH4 has the least molar mass (16gm), so it would occupy the highest volume for 1gm of the gas as higher the molar mass, the lesser is the volume occupied. (b) Similarly, NO has the highest...
H2O exists in three different states of matter. It exists in the solid form as ice, in the liquid form as water and as steam in the gaseous state. All of these states consist of water, due to which...
The correct option is (ii) and (iv).
The correct options are (ii) and (iii).
The correct options are (i) and (iv).
Option (ii) and (iii) are the correct statements.
The correct option is (ii) Decreases.
The correct option is (iii) Decrease.
Steps of construction: Define a boundary portion \[AB\text{ }=\text{ }5\text{ }cm.\] Develop a right point \[SAB\]at point \[A.\] Draw a circular segment of span \[12\text{ }cm\]with \[B\]as its...
Steps of construction: Define a boundary fragment, \[AB\text{ }=\text{ }7\text{ }cm.\] Draw a beam, \[AX\], making an intense point down ward with \[AB.\] Imprint the focuses\[{{A}_{1}},\text{...
False Support: Allow us to attempt to build the figure as given in the inquiry. Steps of development, Define a boundary section \[BC.\] With \[B\text{ }and\text{ }C\]as focuses, draw two circular...
True Support: As per the inquiry, Ratio\[=\text{ }\surd 3\text{ }:\text{ }\left( \text{ }1/\surd 3 \right)\] On working on we get, \[\surd 3/\left( 1/\surd 3 \right)\text{ }=\text{ }\left( \surd...
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Steps of construction: Draw a circle with focus \[\mathbf{O}\]and radius \[\mathbf{3}\text{ }\mathbf{cm}.\] Draw one more circle with focus \[\mathbf{O}\]and radius \[\mathbf{5}\text{...
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Steps of construction: Β Define a boundary \[\mathbf{AB}=\mathbf{3}\text{ }\mathbf{cm}.\] Draw a beam \[\mathbf{BY}\]making an intense \[\angle \mathbf{ABY}=\mathbf{60}{}^\circ .\] With focus...
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![\[\mathbf{60}{}^\circ \]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-dd2bb0881db8f067898bbb2f484f22b0_l3.png "Rendered by QuickLaTeX.com")
![\[\mathbf{AB}\text{ }=\text{ }\mathbf{5}\text{ }\mathbf{cm}\text{ }\mathbf{and}\text{ }\mathbf{AC}\text{ }=\text{ }\mathbf{7}\text{ }\mathbf{cm}.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-b1793bb851dec450a0e88ba1fae151c7_l3.png "Rendered by QuickLaTeX.com")
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![\[\mathbf{AP}\text{ }=\text{ }{\scriptscriptstyle 3\!/\!{ }_4}\text{ }\mathbf{AB}\text{ }\mathbf{and}\text{ }\mathbf{AQ}\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_4}\text{ }\mathbf{AC}.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-7eacd8c8751e5f1f7360fe85877fd895_l3.png "Rendered by QuickLaTeX.com")
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Steps of construction: 1.Define a boundary portion \[AB\text{ }=\text{ }5\text{ }cm.\] Draw \[\angle BAZ\text{ }=\text{ }60{}^\circ .\] With focus \[A\]and sweep\[7\text{ }cm\], draw a...
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![\[{{\mathbf{A}}_{\mathbf{1}}},\text{ }{{\mathbf{A}}_{\mathbf{2}}},\text{ }{{\mathbf{A}}_{\mathbf{3}}},\text{ }\ldots \]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-922e7c66bc6a00de501ae60c8c9b78ff_l3.png "Rendered by QuickLaTeX.com")
![\[{{\mathbf{B}}_{\mathbf{1}}},\text{ }{{\mathbf{B}}_{\mathbf{2}}},\text{ }{{\mathbf{B}}_{\mathbf{3}}},\text{ }\ldots \]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f8d1704d707366f7df0e55622fa1c93e_l3.png "Rendered by QuickLaTeX.com")
![\[\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{5}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{6}}}~\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-89ab77fc48ffa6dcefdea543900ef628_l3.png "Rendered by QuickLaTeX.com")
![\[\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{6}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{5}}}~\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-5256cc8ae0ac0b01612bea1f88f4a203_l3.png "Rendered by QuickLaTeX.com")
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\[\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{5}}}~\mathbf{and}\text{ }{{\mathbf{B}}_{\mathbf{6}}}\] As per the inquiry, A line portion \[AB\]in the proportion \[5:7\] Along these...
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![\[{{\mathbf{A}}_{\mathbf{1}}},\text{ }{{\mathbf{A}}_{\mathbf{2}}},\text{ }{{\mathbf{A}}_{\mathbf{3}}},\ldots .\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e8bbd12bc9b45168d39ff2d0bcc0108e_l3.png "Rendered by QuickLaTeX.com")
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![\[\left( \mathbf{A} \right)\text{ }{{\mathbf{A}}_{\mathbf{12}}}~\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}~\left( \mathbf{C} \right)\text{ }{{\mathbf{A}}_{\mathbf{10}}}~\left( \mathbf{D} \right)\text{ }{{\mathbf{A}}_{\mathbf{9}}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-bda43f24e7ebd73ad31bbcc4874f4781_l3.png "Rendered by QuickLaTeX.com")
SOLUTION:- \[\left( \mathbf{B} \right)\text{ }{{\mathbf{A}}_{\mathbf{11}}}\] As per the inquiry, A line section\[~AB\] in the proportion \[4:7\] Thus, \[A:B\text{ }=\text{ }4:7\] Presently, Draw a...
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SOLUTION:- \[\left( D \right)\text{ }12\] As indicated by the inquiry, A line fragment \[AB\]in the proportion \[5:7\] In this way, \[A:B\text{ }=\text{ }5:7\] Presently, Draw a beam \[AX\]making an...
The correct option is (i) B only.
The correct option is (i) Shimla
The correct option is (ii) Nsmβ2
The correct option is (iv) O2, N2, H2, He.
The correct option is (i) increases.
The correct option is (iii) less than unit electronic charge.
The correct option is (ii) surface tension.
Solution: (i) The numberΒ divisible by 9Β between 100 and 200 = 108, 117, 126,...198 Let n be the number of terms that are divisible by 9 and areΒ between 100 and 200. ${{a}_{n}}~=\text{ }a\text{...
Solution: We all know that, First term of an AP = a The common difference = d APβs nthΒ term of an, ${{a}_{n}}~=a+\left( n1 \right)d$ Since, $n\text{ }=\text{ }37$ (odd), Middle term will be $\left(...
Solution: We all know that, APβs first term = a APβs common difference = d APβs nthΒ term, ${{a}_{n}}~=\text{ }a\text{ }+\text{ }\left( n\text{ }\text{ }1 \right)d$ According to the question,...
Solution: We all know that, Multiple of 2 + Multiple of 5 - LCM Multiple (2, 5) = Multiples of 2 or 5 Multiple of 2 + Multiple of 5 β Multiple of LCM (10) = Multiples of 2 or 5 List of multiple of 2...
Solution: (i) It isΒ known to us that, LCM of (2, 5) = 10 for multiples of 2 and 5. Between 1 and 500, multiples of 2 and 5 = 10, 20, 30,..., 490. As a result, We can say that 10, 20, 30,..., 490 is...
Solution: In an A.P, we know that, First term = a The common difference = d An APβs number of terms of = n According to the question, We have, ${{S}_{5}}~+\text{ }{{S}_{7}}~=\text{ }167$ Using the...
Solution: It is known to us that, APβs first term = a The common difference = d. According to the question given, 5thΒ term, ${{a}_{5}}~=\text{ }19$ Using the nthΒ term formula, ${{a}_{n}}~=\text{...
Solution: The below given condition needs to be satisfied for a, 7, b, 23, c⦠to be in AP, ${{a}_{5}}-{{a}_{4}}~=\text{ }{{a}_{4}}-{{a}_{3}}~=\text{ }{{a}_{3}}-{{a}_{2}}~=\text{...
Solution: (i)Β It is known to us that, APβs first three terms are : a, a + d, a + 2d β2, β2+1/β2, β2+2/β2 β2, 3/β2, 4/β2
Solution: (i)Β It is known to us that, APβs first three terms are : a, a + d, a + 2d ${\scriptscriptstyle 1\!/\!{ }_2},\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\text{ }+\text{ }\left( -1/6...
Solution: Given Here a1Β = a ${{a}_{2}}~=\text{ }2a\text{ }+\text{ }1$ ${{a}_{3}}~=\text{ }3a\text{ }+\text{ }2$ ${{a}_{4}}~=~4a\text{ }+\text{ }3$ ${{a}_{2}}-{{a}_{1}}~=\text{ }\left( 2a\text{...
Solution: (i) Given here, ${{a}_{1~}}=\surd 3$ ${{a}_{2}}~=2\surd 3$ ${{a}_{3}}~=3\surd 3$ ${{a}_{4}}~=4\surd 3$ ${{a}_{2}}-{{a}_{1}}=2\sqrt{3}-\sqrt{3}=\sqrt{3}$ ${{a}_{3}}-{{a}_{2}}~=3\surd...
Solution: (i) Given here, ${{a}_{1~}}=0$ ${{a}_{2}}~=\text{ }{\scriptscriptstyle 1\!/\!{ }_4}$ ${{a}_{3}}~=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}$ ${{a}_{4}}~=\text{ }{\scriptscriptstyle 3\!/\!{...
Column A Column B (A1) 2, β 2, β 6, β10,β¦ (B1) 2/3 (A2)Β aΒ = β18,Β nΒ = 10,Β anΒ = 0 (B2) β 5 (A3)Β aΒ = 0,Β a10Β = 6 (B3) 4 (A4)Β a2Β = 13,Β a4Β =3 (B4) β 4 (B5) 2 (B6) 1/2 (B7) 5 Solution: (A1) AP is 2, β 2, β...
Solution: Consider two APs with the first terms as βaβ and βAβ. The common differencesΒ are βdβ and βDβ, respectively. Assume that n is any term. ${{a}_{n}}~=a+\left( n-1 \right)d$ ${{A}_{n}}~=\text{...
Solution: True Provided that The first term, $a=-3$ The common difference, $d=\text{ }{{a}_{2}}~-{{a}_{1}}~=-7\left( -\text{ }3 \right)=-4$ ${{a}_{30}}-{{a}_{20}}~=\text{ }a+29d-\left( a\text{...
Solution: False ${{a}_{1}}~=\text{ }-1,\text{ }{{a}_{2}}~=\text{ }-3/2,\text{ }{{a}_{3}}~=\text{ }-2$and ${{a}_{4}}~=\text{ }5/2$ ${{a}_{2}}-{{a}_{1~}}=-3/2\left( -1 \right)\text{ }=-1/{{}_{2}}$...
Solution: We have, ${{a}_{1~}}=\text{ }\surd 3$ $,{{a}_{2}}~=\text{ }\surd 12,\text{ }{{a}_{3}}~=\text{ }\surd 27$ and ${{a}_{4}}~=\text{ }\surd 48$ ${{a}_{2}}~-{{a}_{1~}}=\text{ }\surd 12-\surd...
Solution: (i) We have ${{a}_{1}}~=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}~,\text{ }{{a}_{2}}~=\text{ }1/3~$and ${{a}_{3}}~=~{\scriptscriptstyle 1\!/\!{ }_4}$ ${{a}_{2}}~-{{a}_{1}}~=-1/6$ We can...
Solution: (i) We have ${{a}_{1}}~=\text{ }1\text{ },\text{ }{{a}_{2}}~=\text{ }1,\text{ }{{a}_{3}}~=\text{ }2$ and ${{a}_{4}}~=\text{ }2$ ${{a}_{2}}~-{{a}_{1}}~=\text{ }0$...
Solution: (i) We have${{a}_{1}}~=-1\text{ },\text{ }{{a}_{2}}~=-1$, ${{a}_{3}}~=-1$and ${{a}_{4}}~=-1$ ${{a}_{2}}~-{{a}_{1}}~=\text{ }0$ ${{a}_{3}}~-{{a}_{2}}~=\text{ }0$...
Solution: Option (C) 25 is the correct answer. Explanation: Provided, the common difference of AP i.e., d = 5 Now, As it is known, an APβs nth term is ${{a}_{n\text{ }}}=~a+\left( n-1 \right)d$...
Solution: Option (B) 10th is the correct answer. Explanation: Let the given APβs nth term be 210. According to question, first term, $a=21$ common difference, $d=42-21=21$and ${{a}_{n}}~=210$ We...
Solution: Option (B) 33 is the correct option. Explanation: It is known that the APβs nth term is ${{a}_{n\text{ }}}=~a\text{ }+\text{ }\left( n-1 \right)d$ In which, first term = a nth term = an...
Solution: Option (B) 137 is the correct option. Explanation: First two terms of an AP are $a=-3$and${{a}_{2\text{ }}}=~4$. It is known, nth term of an AP is ${{a}_{n\text{ }}}=~a\text{ }+\text{...
Solution: Option (C) β 2, β 4, β 6, β 8 is the correct answer. Explanation: First term, a = β 2 Second Term, d = β 2 ${{a}_{1\text{ }}}=~a=\text{ -}2$ It is known that the APβs nth term is...
Solution: Option (B) 20 is the correct answer. Explanation: First term, a = β 5 Common difference, $d=5-\left( -5/2 \right)=5/2$ $n\text{ }=\text{ }11$ It is known that the APβs nth term is...
Solution: Option (B) an AP with d = 4 is the correct answer. Explanation: According to the question, ${{a}_{1\text{ }}}=~\text{ }-10$ ${{a}_{2\text{ }}}=\text{ }-6$ ${{a}_{3\text{ }}}=~\text{ }-2$...
Solution: Option (B) 3.5 is the correct answer. Explanation: It is known that nth term of an AP is ${{a}_{n\text{ }=}}~a+\left( n1 \right)d$ In which, first term = a nth term = an common difference...
Solution: According to the given question, DE || AB By the basic proportionality theorem, $CD/AD\text{ }=\text{ }CE/BE$ Therefore, when a line is drawn parallel to one of the triangle's sides and...
Solution: False According to the given question, Letβs assume that, $A\text{ }=\text{ }25\text{ }cm$ $B\text{ }=\text{ }5\text{ }cm$ $C\text{ }=\text{ }24\text{ }cm$ Using the Pythagoras Theorem, We...
Solution: (i) Let (p, q) be the coordinates of a point Q. Provided, The point Q (p, q), Divide the line joining $\mathrm{B}\left(\mathrm{x}{2}, \mathrm{y}{2}\right)$ and...
Solution: According to the given question, A, B and C are the vertices of ΞABC A(x1, y1), B(x2, y2), C(x3, y3) are the coordinates of A, B and C. (i) According to the information provided, D is BC's...
Solution: According to the given question, A (6, 1), B (8, 2) and C (9, 4) are the three vertices of a parallelogram ABCD Let (x, y) be the fourth vertex of parallelogram. It is known to us that,...
Solution: Option (D) 28 is the correct answer. Explanation: It is known that nth term of an AP is ${{a}_{n\text{ }=}}~a+\left( n-1 \right)d$ In which, first term = a nth term = an common difference...
Solution: Let (x,y) be the vertices. The distance between (x,y) & (4,3) is $=\text{ }\surd ({{\left( x-4 \right)}^{2}}~+\text{ }{{\left( y-3 \right)}^{2}})$β¦β¦(1) The distance between (x,y) &...
Solution: Let 1: k be the ratio in which x-axis divides the line segment joining (β4, β6) and (β1, 7). Therefore, x-coordinate is (-1 β 4k) / (k + 1) y-coordinate is (7 β 6k) / (k + 1) y coordinate...
Solution: The provided vertices are: $({{x}_{1}},\text{ }{{y}_{1}})\text{ }=\text{ }\left( -8,\text{ }4 \right)$ $({{x}_{2}},\text{ }{{y}_{2}})\text{ }=\text{ }\left( -6,\text{ }6 \right)$...
solution: \[\begin{array}{*{35}{l}} W=\text{ }\text{ }2.303nRT\text{ }log\text{ }\left( p1/p2 \right)Β \\ ~Β \\ =\text{ }\text{ }2.303\text{ }\times \text{ }1\text{ }mol\text{ }\times \text{...
solution: From the given enthalpy outline it tends to be said the adjustment of enthalpy βH is positive for the response, for example it will be endothermic. In any case, when goes to the suddenness...
![\[\left( b \right)\text{ }1/2\text{ }H2\left( g \right)\text{ }+\text{ }1/2\text{ }Cl2\left( g \right)\leftrightharpoons HCl\left( g \right)\Delta rH\Theta =92.32\text{ }kJ\text{ }mol1\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-2732efbedd48f360b154aff012982f0c_l3.png "Rendered by QuickLaTeX.com")
solution: Among these two cycles, simultaneously or response (b) the expected energy/enthalpy change is contributing component to the immediacy.
solution: At the point when an optimal gas in a pressure, where the adjustment of tension is completed in boundless advances for example through a reversible interaction, the work done can be...
solution: From this chart we can get the be the work done on the ideal gas encased in the chamber in 1 stage: the region covered by P-V diagram (concealed locale) is the real worth of the...
Solution: $A(2,-4), P(3,8)$ and $Q(-10, y)$ are the given points. Now according to the question given, $$ \begin{aligned} P A &=Q A \\ \sqrt{(2-3)^{2}+(-4-8)^{2}} &=\sqrt{(2+10)^{2}+(-4-y)^{2}} \\...
solution: In the accompanying cyclic ( 1 β 2 β3 β1 ) measure the underlying and last point is something very similar (for example 1). Subsequently the enthalpy change or\[H=\text{ }0\]...
Solution: The points given here i.e., A(5, 1), B(β2, β3) and C(8, 2m) are collinear. Therefore the area of βABC = 0 ${\scriptscriptstyle 1\!/\!{ }_2}\text{ }[{{x}_{1}}~({{y}_{2}}~\text{...
Solution: As the point P lies on the perpendicular bisector of AB, point Q is the midpoint of AB . By the formula for midpoint: $({{x}_{1}}~+\text{ }{{x}_{2}})/2\text{ }=\text{ }\left( -5+4...
![\[\begin{array}{*{35}{l}} \left( I \right)\text{ }w\text{ }\left( reversible \right)\text{ }=\text{ }w\text{ }\left( irreversible \right) \\ ~ \\ \left( ii \right)\text{ }w\text{ }\left( reversible \right)\text{ }<\text{ }w\text{ }\left( irreversible \right) \\ ~ \\ \left( iii \right)\text{ }w\text{ }\left( reversible \right)\text{ }>\text{ }w\text{ }\left( irreversible \right) \\ ~ \\ \left( iv \right)\text{ }w\text{ }\left( reversible \right)\text{ }=\text{ }w\text{ }\left( irreversible \right)\text{ }+\text{ }pex.V \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-cd21a1dca804f61b0640fc61b9848d76_l3.png "Rendered by QuickLaTeX.com")
Arrangement: Alternative (ii) is the appropriate response. w (reversible) < w (irreversible) Region under the bend is more noteworthy in irreversible pressure than that of reversible...
Solution: Let P be the point. Now according to the given question, P is at equal distance from A (β5, 4) and B (β1, 6) Then the point P $=\text{ }(({{x}_{1}}+{{x}_{2}})/2,\text{...