Solution: Cyclo-octatetraene isn't planar yet is tub-molded. It is, in this manner, a non-planar framework having 8 n-electrons. In this manner, the atom isn't sweet-smelling as it doesn't contain a...
Solution: Because of the presence of sp3–hybridized carbon, the framework isn't planar. Further, it contains just four n-electrons, subsequently, the framework isn't fragrant on the grounds that it...
Solution: Because of the presence of a sp3-hybridized carbon, the framework isn't planar. It contains six n-electrons yet the framework isn't completely formed since all the six n-electrons don't...
Solution: The fundamental conditions for any fragrant framework are as per the following: (I) Firstly, the compound course of action or construction ought to be planar. (ii) The n-electrons are...
Solution: Benzene is a mixture of the resounding designs and it is displayed as: Every one of the six carbon molecules in benzene are hybridized to sp2.In benzene, every carbon particle's two...
Solution: Hex-2-ene is addressed as displayed beneath: Mathematical isomers of hex-2-ene are as per the following: A cis intensifies dipole second is equivalent to the amount of the C – CH3...
Solution: Burning responses might be characterized as an oxygen or oxygen response of a compound.
Solution: Burning responses might be characterized as an oxygen or oxygen response of a compound.
Solution: Burning responses might be characterized as an oxygen or oxygen response of a compound.
Solution: Burning responses might be characterized as an oxygen or oxygen response of a compound.
Solution: From the given data, the two ozonolysis results of an alkene are pentan-3-one and propanal. Assume the alkene given is A. The converse of the ozonolysis response is the thing that we get,...
Solution: From the data given it gives two moles of an aldehyde of molar mass 44 u when ' A ' goes through ozonolysis. The arrangement of an aldehyde's two moles recommends that the presence of...
Throughout ozonolysis, an ozonide is created as a halfway that has a cyclic construction; it goes through cleavage to give the eventual outcomes. Ethanal and pentan-3-one are acquired from the...
Solution: Ozonolysis of 1 – Phenylbut-1-ene is displayed as The resulting IUPAC names of the items are : Item (I) benzaldehyde, and Item (II) propanal
Solution: Ozonolysis of 2-Ethylbut-1-ene is displayed as: The resulting IUPAC names of the items are: Item (I) pentan-3-one, and Item (II) methanal
Solution: Ozonolysis of 3, 4-Dimethylhept-3-ene is displayed as: The item names resulting to IUPAC are: Item (I) butan-2-one, and Item (II) Pentan-2-one
Solution: Ozonolysis of Pent-2-ene is displayed as: The accompanying Product IUPAC names are: Item (I) ethanal, and Item (II) propanal.
Solution: The resulting primary isomers are likely for C5H8 with one triple bond: The IUPAC name of Compound (I) is Pent-1-yne, Compound (II) is Pent-2-yne, and Compound (III) is...
Solution: The subsequent primary isomers with one twofold bond are plausible for C4H8: The IUPAC name of Compound (I) is But-1-ene, Compound (II) is But-2-ene, and Compound (III) is...
Solution: 4-Ethyldeca-1, 5, 8-triene is the necessary IUPAC name
Solution: 5-(2-Methylpropyl)- decane is the necessary IUPAC name
Solution: 2-Methyl phenol is the necessary IUPAC name
Solution: 4-Phenyl but-1-ene is the necessary IUPAC name
Solution: 1, 3-Butadiene or Buta-1,3-diene is the necessary IUPAC name
Solution: Pen-1-ene-3-yne is the necessary IUPAC name
![\[\mathbf{C}{{\mathbf{H}}_{\mathbf{3}}}~\mathbf{CH}\text{ }=\text{ }\mathbf{C}\text{ }{{(\mathbf{C}{{\mathbf{H}}_{\mathbf{3}}})}_{\mathbf{2}}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-c63b9b35d0c7e5500238909182cb534b_l3.png "Rendered by QuickLaTeX.com")
Solution: 2-Methylbut-2-ene is the necessary IUPAC name
Solution: The methane chlorination measure works through a free extreme chain instrument. Stage 1: Initiation: The outcome starts with the hemolytic cleavage of Cl – Cl bond as: Stage 2:...
. If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.It is given that neutron was at rest before $\beta$ decay from neutron. So, energy of neutron $=$ $\mathrm{E}_{\mathrm{n}}=\mathrm{m}_{\mathrm{n}} \mathrm{c}^{2}$. Momentum of neutron...
The binding energy of a deuteron is given as $B = 2.2 MeV$ The kinetic energies of neutron and proton be $K_n$ and $K_p$ $p_n$ and $p_p$ are the momentum of neutron and proton $E - B = K_n + K_p$ B...
.$\lambda=\mathrm{h} / \mathrm{p}$ and, kinetic energy $=$ potential energy $\mathrm{E}=\mathrm{hc} / \lambda$ Kinetic energy of an electron can be calculated as, $\mathrm{KE}=\mathrm{PE}=\mathrm{hc}...
activity of 12 disintegrations per minute per gram of its carbon content. The 
activity of the living wood is 16 disintegrations per minute per gram. How long ago did the tree, from which the wooden sample came, die? Given the half-life of is 5760 years.$\mathrm{C}^{14}$ activity of a piece of wood from the ruins is given as $\mathrm{R}=12 \mathrm{dis} / \mathrm{min}$ per gram $\mathrm{C}^{14}$ activity of a living wood is given as...
and 
are the disintegration constants of A and B respectively. In which of the following cases, the two samples can simultaneously have the same decay rate at any time?
and 
The correct options are: (b) Initial rate of decay of A is twice the initial rate of decay of B and $\lambda _A>\lambda_B$ (d) Initial rate of decay of B is the same as the rate of decay of A at...
The correct option is: (b) elastic collision of neutrons with heavy nuclei will not slow them down
and 
denote the atomic masses of the parent and the daughter nuclei respectively in a radioactive decay. The Q-value for a 
– decay is 
and that for a 
decay is 
. If me denotes the mass of an electron, then which of the following statements is correct?
and 
and 
and 
and The correct option is: (a) $Q_ 1=(M _x-M_ y) c^{2}$ and $Q_ 2=(M _x-M_ y-2 m_ e) c^{2}$
Answer: When two separate atoms join to form a covalent connection, their electrons are not shared equally. A more electronegative atom's nucleus attracts the bond pair. In this case, an...
Answer: Sr. No Electronegativity Electron affinity 1 The electronegativity of an atom in a chemical compound refers to its proclivity to attract the shared pairs of electrons that are present in the...
ion.Answer: Although the properties of the carbonate ion cannot be described by a single structure, they can be described by two or more resonance structures. The carbonate ion's true structure is a...
Answer: Ammonia's central atom (N) has 1 lone pair and 3 bond pairs. Water's central atom (O) has two lone pairs and two bond pairs. The two lone pairs on the O- atom of water reject the two bond...
Answer: An ionic link is formed by moving electrons from one atom to another. This means that ionic bond formation is dependent on neutral atom flexibility. The lattice energy of the molecule...
Answer: "Atoms can combine either by transferring or sharing valence electrons to achieve the closest inert gas configuration," says the Octet Rule. Octet rule describes how chemical bonds occur...
Answer: “A chemical bond is an attractive force that binds chemical elements together.” Many theories exist for forming chemical bonds, including valence shell electron pair repulsion, electronic,...
Solution: Ne displays neither negative nor positive oxidation no. That is 0.
Solution: I displays both negative and positive oxidation no. That is - 1, +1, +3, +5 and +7.
Solution: Cs displays just certain oxidation no. That is +1.
Solution: F exhibits only negative oxidation number. That is -1.
Solution: $\mathrm{KAl}\left(\underline{\mathrm{S}} \mathrm{O}_{4}\right)_{2} .12 \mathrm{H}_{2} \mathrm{O}$ Let expect oxidation number of S is x. \[\begin{array}{*{35}{l}}...
Solution: $\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{7}$ Let accept oxidation number of S is x. \[\begin{array}{*{35}{l}} Oxidation\text{ }number\text{ }of\text{ }O\text{ }=\text{...
Solution: NaBH4 Let accept oxidation number of B is x. \[\begin{array}{*{35}{l}} Oxidation\text{ }number\text{ }of\text{ }Na\text{ }=\text{ }+1 \\ ~ \\ Oxidation\text{ }number\text{...
to prove 
, prove that 
a) Substituting the above equations in the following equation we get ${c} \oint E . d l=-\frac{d \phi_{B}}{d t}=-\frac{d}{d t} \oint B \cdot d s$ So, $E_{0} / B_{0}=0$ b) We get $c=1 /...
Solution: CaO2 Let expect oxidation number of O is x. \[Oxidation\text{ }number\text{ }of\text{ }Ca\text{ }=\text{ }+2\] Then, at that point, we have: \[\begin{array}{*{35}{l}}...
Solution: K2MnO4 Let expect oxidation number of Mn is x. \[\begin{array}{*{35}{l}} Oxidation\text{ }number\text{ }of\text{ }K\text{ }=\text{ }+1 \\ ~ \\ Oxidation\text{ }number\text{...
Solution: H4P2O7 Let expect oxidation number of P is x. \[\begin{array}{*{35}{l}} Oxidation\text{ }number\text{ }of\text{ }H\text{ }=\text{ }+1 \\ ~ \\ Oxidation\text{ }number\text{...
Solution: NaHSO4 Let expect oxidation number of S is x. \[\begin{array}{*{35}{l}} Oxidation\text{ }number\text{ }of\text{ }Na\text{ }=\text{ }+1 \\ ~ \\ Oxidation\text{ }number\text{...
Solution: NaH2PO4 Let expect oxidation number of P is x. We realize that, \[\begin{array}{*{35}{l}} Oxidation\text{ }number\text{ }of\text{ }Na\text{ }=\text{ }+1 \\ ~ \\...
Solution: (b) Graphite is thermodynamically the most steady type of carbon.
is placed along the z-axis. The wire is set into motion along its length with a uniform velocity 
Calculate the pointing vectors 
The electric field in an infinitely long thin wire is given by the expression, $\vec{E}=\frac{\lambda \hat{e}_{s}}{2 \pi \epsilon_{0} a} \hat{j}$ Magnetic field due to the wire is given by the...
Solution: (c) Boron in diborane is sp3 hybridized.
Solution: (b) Borax is a strong base salt (NaOH) and a frail corrosive (H3BO3). Accordingly, it is an essential thing in nature.
Solution: Catenation A few components or particles (like carbon) may interface with one another through solid covalent bonds to shape long chains or branches. This trademark is known as catenation....
Solution: Allotropy Allotropy is the presence of a component in more than one structure, having distinctive actual properties yet similar synthetic properties. The various types of a component are...
Solution: Inert pair impact As one actions down the gathering, s-block electrons decline their propensity to take part in substance holding. This impact is known as the dormant pair impact. The...
Solution: Thallium is a piece of the intermittent table gathering 13. For this gathering, the most widely recognized oxidation state is + 3. Heavier individuals from this gathering, nonetheless,...
Solution: Carbon ionizing enthalpy (the principal component in bunch 14) is exceptionally high (1086 kJ/mol). That is normal due to its little size. Nonetheless, there is a sharp decline in enthalpy...
Solution: Aluminum wire is utilized to make transmission links. Aluminium wires are good conductors of electricity and also it is cheap metal easily available, light in weight and also very ductile....
Solution: Aluminum utensils ought not be kept in water for the time being. The oxygen in water responds to make a dainty layer of aluminum oxide with aluminum. This layer keeps further response from...
Solution: Aluminum compounds are utilized to make airplane body. Aluminum has a high protection from elastic and is light. It might likewise be alloyed to various metals like Si, Mg, Cu, Mn and Zn....
Solution: Diamond is utilized as a rough Carbon is sp3 hybridized in Diamond. With the assistance of solid covalent bonds, every carbon molecule is bound to four other carbon iotas. These covalent...
Solution: Graphite is utilized as the grease. Graphite has a layered construction, and the powers of frail van der Waals tie various layers of graphite together. These layers might slide one over...
Solution: A combination of weaken NaOH and aluminum pieces is utilized to open the channel. Sodium hydroxide and aluminum respond to shape aluminate (III) sodium tetra hydroxy and hydrogen gas....
Solution: Conc.HNO3 can be shipped in an aluminum holder. As it responds with aluminum to frame a slight defensive oxide layer on the aluminum surface, concentrated HNO3 can be put away and shipped...
Solution: Carbon dioxide is a gas that is vital for our endurance. The expanded CO2 content in the climate, nonetheless, represents a genuine danger. An increment in petroleum product ignition,...
Solution: Given its capacity to frame a complex with hemoglobin, carbon monoxide is profoundly toxic. The previous hinders restricting with oxygen by Hb. Subsequently, an individual passes on...
parallel plate capacitor. How would you establish an instantaneous displacement current of 
in the space between its plates?The capacitance of the capacitor is given by $\mathrm{C}=2 \mu \mathrm{F}$ Displacement current is given as $I_{d}=1 \mathrm{~mA}$ Hence, Charge in capacitor will be, $q=C V$ $\mathrm{dV} /...
Solution: Chromatography It is generally utilized for the partition and cleansing of natural mixtures. Rule: The guideline on which it works is that singular parts of a blend move at various speeds...
Solution: Distillation This strategy is utilized to isolate non-unpredictable fluids from unstable pollutants. It is likewise utilized when the parts have an extensive distinction in their edges of...
Solution: Crystallization Crystallization is utilized to decontaminate strong natural mixtures. Standard: The guideline on which it works is the distinction in the dissolvability of the compound and...
Solution: Substitution (nucleophilic) response since modification of particles happens.
Solution: Elimination (bimolecular) response since response hydrogen and bromine are taken out to shape ethene.
Solution: Addition (electrophilic) response since two reactant particles joins to shape a solitary item.
Solution: Substitution (nucleophilic) response since bromine bunch gets subbed by – SH bunch.
Solution: A nucleophile is a reagent that has an electron pair and will give it away. It is otherwise called a core adoring reagent. An electrophile is a reagent which needs an electron pair and is...
Solution: A nucleophile is a reagent that has an electron pair and will give it away. It is otherwise called a core adoring reagent. An electrophile is a reagent which needs an electron pair and is...
Solution: A nucleophile is a reagent that has an electron pair and will give it away. It is otherwise called a core adoring reagent. An electrophile is a reagent which needs an electron pair and is...
Solution: A nucleophile is a reagent that has an electron pair and will give it away. It is otherwise called a core cherishing reagent. Ex: NC–, OH–, R3C–(carbanions), and so on An electrophile is a...
Solution: Since NO2 has a place with the electron-pulling out bunch, it shows – I impact. NO2 attempts to diminish the negative charge on the compound by pulling out the electrons toward it. This...
Solution: The initial five individuals from each homologous series starting with the given mixtures are H–CH=CH2: Ethene CH3–CH=CH2: Propene CH3–CH2–CH=CH2: 1-Butene CH3–CH2–CH2–CH=CH2: 1-Pentene...
Solution: CH3COCH3: Propanone CH3COCH2CH3: Butanone CH3COCH2CH2CH3 : Pentan-2-one CH3COCH2CH2CH2CH3: Hexan-2-one CH3COCH2CH2CH2CH2CH3 : Heptan-2-one
is defined as a vector whose magnitude is equal to the wave intensity and whose direction is along the direction of wave propagation. Mathematically, it is given by 
. Show that nature of versus 
graph.Solution: The initial five individuals from each homologous series starting with the given mixtures are H–COOH: Methanoic corrosive CH3–COOH: Ethanoic corrosive CH3–CH2–COOH: Propanoic corrosive...
Solution: Out of the two utilitarian gatherings present in the given compound, the alcoholic gathering is the central practical gathering. Consequently, the parent chain will have an – ol postfix....
. The plates are very large and close together. Neglecting the edge effects, find the displacement current through the capacitor?Displacement current through the capacitor is given as, $\mathrm{Id}=\mathrm{Ic}=\mathrm{dq} / \mathrm{dt}$ Given, $q=q_{0} \cos 2 \pi v t$ On putting the values, we get $\mathrm{Id}=\mathrm{Ic}=-2...
Solution: If the substituents in the chain are in identical positions, then, at that point, the lower number is given to the substituent bunch in sequential request. Along these lines, the right...
Solution: The locant number should begin from the base. Here, 2,4,7 is lower than 2,5,7. Subsequently, the right IUPAC name would be 2,4,7-Trimethyloctane.
solution: The prefix di shows that there are two methyl bunches in the chain. Along these lines, the right IUPAC name would be 2,2-Dimethylpentane.
As electromagnetic waves are plane polarised, the antenna must be parallel to the vibration of the fields of the wave. The orientation of the portable radio with respect to the transmitting station...
![\[C6H6\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-250e7c087123a8d0267c095925b18800_l3.png "Rendered by QuickLaTeX.com")
Solution: C6H6 All the 6 carbon particles in benzene are sp2 hybridized
![\[CH2=CHCN\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-52ef84ac98a604743dfb23732dfbb165_l3.png "Rendered by QuickLaTeX.com")
Solution: C-1 is sp2 hybridized. C-2 is sp2 hybridized. C-3 is sp hybridized.
![\[\left( CH3 \right)2CO\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a2bea77220b7e99546204fa04a862cfa_l3.png "Rendered by QuickLaTeX.com")
Solution: C - 1 and C-3 are sp3 hybridized. C-2 is sp2 hybridized.
![\[CH3CH=CH2\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-6a2ef16862caa7e37fd3861c7df53de4_l3.png "Rendered by QuickLaTeX.com")
Solution: C-1 is sp3 hybridized. C-2 is sp2 hybridized. C-3 is sp2 hybridized.
![\[CH2=C=O\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-3ffdae7fcb2301f4db1b66d768c446ab_l3.png "Rendered by QuickLaTeX.com")
Solution: C-1 is sp2 hybridized. C-2 is sp hybridized.
-direction can have the following pairs of 
and 
The correct options are: b) $E_y, \mathbf{B_ z}$ d) $E_z, B_y$
-axis is given as: 
. Choose the correct options from the following a) the associated magnetic field is given as 
a) the associated magnetic field is given as $B=\frac{1}{c} \hat{k} \times E=\frac{1}{\omega}(\hat{k} \times E)$ b) the electromagnetic field can be written in terms of the associated magnetic field...
c) ultraviolet region
R must be short-circuited in order for the circuit to become an LC oscillator. The capacitor will continue to drain, and all of the energy will be transferred to L and back. Energy will oscillate...
(b) 5 √3/2 A
Answer: (b) F > O > Cl > N During a period, as we move from left to right, the non-metallic characteristics of the elements become more prominent. As a result, F > O > N.
Answer: c) F > N > C > B > Si While moving from left to right in a period, the nonmetallic property of the elements reduces as we move from left to right in the period. As a result, F...
Answer: d) K > Mg > Al > B During a period, the metallic nature of the components diminishes as we move from left to right in the period. As a result, Mg > Al. With each group we...
Answer: (d) is a false statement When comparing orbitals with a lower value of 'n' to orbitals with a higher value of 'n,' it is easier to remove an electron from the lower value of 'n' orbital....
Answer: (a) Nuclear charge (Z) Because, in the case of isoelectronic species, the atomic size decreases as the number of nuclear charge increases (Z). e.g. the arrangement according to increasing...
Answer: Option c) Because the nucleus is made up of protons and neutrons, the mass of the nucleus has no effect on the valence shell. Protons, or nuclear charges, have an effect on the valence...
Answer: Correcting the incorrect statement is represented by option (b). It explains that "the d-block has 8 columns because a maximum of 8 electrons can occupy all of the orbitals in a d-subshell,"...
Answer: (c) The period in the Modern periodic table indicates the value of ‘n’ i.e. a principal quantum number. A periodic table's period reflects the value of a particular element's major quantum...
Answer: i) $Li_2O$ is formed when the alkali metal lithium (with one valence electron) and group 16 element oxygen (with two valence electrons) mix. (ii) The alkaline earth metal magnesium (which...
and the second 
ionization enthalpies (in 
) and the 
electron gain enthalpy (in ) of a few elements are given below: Which of the above elements is likely to be : (a) the least reactive element. (b) the most reactive metal. (c) the most reactive non-metal. (d) the least reactive non-metal. (e) the metal which can form a stable binary halide of the formula MX2 (X=halogen). (f) the metal which can form a predominantly stable covalent halide of the formula MX (X=halogen)?Elements (\Delta _{i}H_{1})(ΔiH1) (\Delta _{i}H_{2})(ΔiH2) (\Delta _{eg}H)(ΔegH) 1 520 7300 -60 2 419 3051 -48 3 1681 3374 -328 4 1008 1846 -295 5 2372 5251 +48 6 738 1451 -40 Answer:...
for 
(ii) (n1) 
for 
, and (iii) 
for 
, in the periodic table.Answer: i) Since n = 6, the element is in period 6. f-block element because the last electron enters f-orbital. They are in the third group. So, 54 + 7 + 2 + 1 Equals 64. So Gadolinium is required....
Answer: The general outer electronic configuration of s block elements is $ns ^{(1-2)}$. The general outer electronic configuration of p block elements is $ns ^{2} np ^{(1-6)}$. The general outer...
Answer: Group 1 elements have only one valence electron. So they tend to expel this electron to form a stable inert gas. The ionization enthalpies of the elements drop in group 1. Expulsion of the...
Answer: (a) The electrical configuration of an element with 5 electrons in the outer subshell is ns2np5. The electrical configuration of the Halogen group is the same. As a result, the elements...
Answer: Metals lose electrons to produce cations. Metals have low ionization, negative electron, and electronegativities enthalpies. ionic compounds and basic oxides Non-metals readily take...
Answer: The ionization enthalpy of any atom is determined by the number of protons and electrons in the atom. However, the isotopes of any element have the same number of electrons and protons as...
Answer: a) An atom loses one electron when it expels one, but the nuclear charge remains the same. In an atom, electron-electron repulsion reduces. So the effective nuclear charge increases. As a...
Answer: Electronegativity is a property of any element that is subject to change. Electronegativity varies depending on the substance being studied. The following statement is erroneous: "The...
Answer: Electron gain enthalpy Electronegativity It is the common tendency of an atom to attract outside electrons It is the general tendency of an atom to attract shared pair of electrons It is the...
Answer: Oxygen is in p block element group 16. It is the first of 16 members. It is a non-metal found in the earth's crust. When an electron is added to an O atom, it releases energy. O has a...
Answer: i) O and F are from the same period. As the electron is inserted in the same shell, the atomic size of O-atom is larger than F-atom. It has one less proton than F-atom. So an O-atom nucleus...
B Al Ga In Tl 801 577 579 558 589 Answer The ionization enthalpy decreases with group size. B and Al agree. Ga has a higher ionization enthalpy than Al. Tend electrons in the inner shell of...
The gravitational force of the earth attracts molecules in the atmosphere, yet they do not descend into the earth since they are in random motion, whereas an apple moves downhill.
Answer: The factors that cause the ionization enthalpy to drop as we travel down the main group are as follows: 1. “Inner shells increase in number as we proceed down the group.” The nucleus' inner...
Answer: Because magnesium has a larger 1st ionization enthalpy than sodium, Magnesium has bigger atoms than sodium. A higher effective nuclear charge than sodium, Magnesium So sodium requires less...
Answer: i) The electron that can be evacuated from Be(beryllium) atom is 2s, but the electron that can be expelled from boron is 2p. 2s – electron, and nucleus attract more strongly than 2s –...
. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol–1.Answer: Given that, the electron of hydrogen is having $-2.18 * 10^{-18} J$ in the ground state. Thus, To eject an electron from the ground state in a $H ($ hydrogen $)-$ atom, a certain amount of...
The correct options are a) planets will not have elliptic orbits c) projectile motion of a stone thrown by hand on the surface of the earth will be approximately parabolic Explanation: The planets...
Answer: In the ground state of an isolated gaseous atom, ionisation enthalpy is required to eject an electron. Even though the atoms are far separated in the gaseous state, there are some attraction...
Answer: It possesses less electrons than the parent atom, but the overall nuclear charge remains the same, resulting in greater attraction of electrons to the nucleus. Cations have smaller radii...
, and 
(a) What is common in them? (b) Arrange them in the order of increasing ionic radii.Answer: (a) All of the species have the same number of electrons, i.e. 10 electrons. They are, therefore, isoelectronic species. (b) The following is the arrangement of the given ions in ascending...
The correct option is c) not be true because the major gravitational force on mercury is due to sun
The correct option is d) cannot be zero at any point
Solution: Hydrogen peroxide goes about as a solid oxidizing specialist both in fundamental and acidic media. When added to a material, it breaks the substance obligations of the chromophores...
Solution: D2O is referred to as weighty water which goes about as an arbitrator (dials back the pace of response). Because of this property, it can't be utilized for drinking reason since it dials...
Solution: Water is extremely important for all types of life which establish 65% of human body and 95% of plants.it assumes an indispensable part in the biosphere because of its → Thermal...
Solution: Water is extremely fundamental for our life. It comprises of many broke down supplements that are needed for ourselves and furthermore for plants and creatures. Demineralised water is...
Solution: This water is liberated from every one of the solvent mineral salts and it doesn't contain any cation or anion. It is acquired progressively by going the water through anion trade and...
Solution: Because of the presence of dissolvable salts of magnesium and calcium as chlorides in water, hardness stays super durable in water. Because of the presence of dissolvable salts of calcium...
Solution: For the most part, ice is the translucent type of water. It visibles in a hexagonal structure in case it is solidified at climatic strain. At the point when the temperature is...
Solution: The water atom will be shown with a bond point of 104 .5o has a bowed structure in vaporous stage. The O-H bond length is 95.7 pm. Structure : Hydrogen peroxide has a non-planar design...
Solution: Ionic hydrides are solid diminishing specialists. NaH can undoubtedly give its electrons. Henceforth, it is most diminishing in nature. Both, MgH2 and H2O are covalent hydrides. H2O is...
Solution: The bond pair in D–D bond is more emphatically drawn in by the core than the bond pair in H–H bond. This is a direct result of the greater atomic mass of D2. The more grounded the...
Solution: The ionic person of a bond is reliant upon the electro negativities of the molecules in question. The higher the distinction between the electro negativities of molecules, the more modest...
Solution: The electrical conductance of an atom chiefly relies upon its covalent or ionic nature. CaH2 is an ionic hydride, which conducts power in the liquid state. Titanium hydride, TiH2 is...
Solution: The degree of hydrogen holding predominantly relies upon (I) Electronegativity (ii) Number of hydrogen iotas accessible for holding. Among oxygen, fluorine and nitrogen, the expanding...
Solution: The nuclear hydrogen light is otherwise called oxy-hydrogen light. These molecules are delivered through dihydrogen separation with the assistance of an electric circular segment which...
Solution: Metallic hydrides are hydrogen inadequate. They don't keep the law of consistent structure. It has been set up that in the hydrides of Pd, Ac, Ni, and Ce, hydrogen possesses the...
Solution: Non-Stoichiometric hydrides are hydrogen-insufficient mixtures which is framed by the response of dihydrogen with d-square and f-block components. These hydrides don't observe the law of...
Solution: For carbon hydrides which have a place with type (Cn H2n+2), the accompanying hydrides are feasible for \[\begin{array}{*{35}{l}} n\text{ }=\text{ }1\Rightarrow CH4 \\ ~ \\...
Solution: Sub-atomic hydride is grouped based on the presence of the bonds and absolute number of electrons in their Lewis structures as: Electron-inadequate hydrides Electron-exact hydrides...
Solution: The ionization enthalpy of H–H bond is higher (1312 kJ mol–1 ) which shows that hydrogen has a low propensity to frame H+ particles. Its ionization enthalpy esteem is equivalent to that of...
Solution: The ionization enthalpy of hydrogen molecule is higher. In this manner, it is more enthusiastically to eliminate its electron. This outcomes its propensity to exist in the low monoatomic...
Solution: The first component in the occasional table is hydrogen. Hydrogen shows double conduct since it has just 1 electron on its one 'S' shell.(i.e.,) hydrogen takes after the two incandescent...
![\[f\text{ }H0=\text{ }\text{ }286\text{ }kJ\text{ }mol1.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0876268cab5e7e19237ca8d099603274_l3.png "Rendered by QuickLaTeX.com")
Solution: It is given that 286 kJ mol–1 of warmth is advanced on the development of 1 mol of H2O(l). Accordingly, an equivalent measure of warmth will be consumed by the environmental elements....
Solution: The positive worth of ∆rH demonstrates that warmth is assimilated during the development of NO(g). This implies that NO(g) has higher energy than the reactants (N2 and O2)....
![\[G0?\text{ }R\text{ }=\text{ }8.314\text{ }JK1\text{ }mol1,\text{ }T\text{ }=\text{ }300\text{ }K.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-c5355a31e6d1d5f6327e806c31f733f0_l3.png "Rendered by QuickLaTeX.com")
Solution: From the articulation, \[\begin{array}{*{35}{l}} G\theta \text{ }=\text{ }\text{ }2.303\text{ }RT\text{ }logKeq \\ ~ \\ G\theta \text{ }for\text{ }the\text{ }response,\text{ }=\text{...
![\[\begin{array}{*{35}{l}} 2A\left( g \right)\text{ }+\text{ }B\left( g \right)\text{ }\to \text{ }2D\left( g \right) \\ ~ \\ U\theta \text{ }=\text{ }\text{ }10.5\text{ }kJ\text{ }and\text{ }S\theta \text{ }=\text{ }\text{ }44.1\text{ }JK1\text{ }. \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-cbc82328853f02bdc578b87abcbd9b11_l3.png "Rendered by QuickLaTeX.com")
Solution: For the given response, \[\begin{array}{*{35}{l}} 2\text{ }A\left( g \right)\text{ }+\text{ }B\left( g \right)\text{ }\to \text{ }2D\left( g \right) \\ ~ \\ ng\text{ }=\text{...
Solution: ∆H and ∆S are negative The given response addresses the development of chlorine particle from chlorine molecules. Here, bond development is occurring. Along these lines, energy is being...
![\[\begin{array}{*{35}{l}} 2A\text{ }+\text{ }B\text{ }\to \text{ }C\text{ }H\text{ }=\text{ }400\text{ }kJ\text{ }mol1 \\ ~ \\ what's\text{ }more,\text{ }S\text{ }=\text{ }0.2\text{ }kJ\text{ }K1\text{ }mol1 \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-dda209e4073843cae616fbc6002155e5_l3.png "Rendered by QuickLaTeX.com")
Solution: From the articulation, \[G\text{ }=\text{ }H\text{ }\text{ }TS\] Expecting the response at balance, ∆T for the response would be: \[\begin{array}{*{35}{l}} \left( G\text{...
![\[U\text{ }=\text{ }0\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-e877d1035c3edbb47c89fe48897ae3da_l3.png "Rendered by QuickLaTeX.com")
Solution: ∆S will be positive i.e., more noteworthy than nothing \[Since\text{ }U\text{ }=\text{ }0,\] ∆S will be positive and the response will be unconstrained.
![\[CCl4\left( g \right)\text{ }\to \text{ }C\left( g \right)\text{ }+\text{ }4Cl\left( g \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-2f50a987d1e8f6ebc394f6ed04c1c2b4_l3.png "Rendered by QuickLaTeX.com")
![\[\begin{array}{*{35}{l}} vapH\theta \text{ }\left( CCl4 \right)\text{ }=\text{ }30.5\text{ }kJ\text{ }mol1\text{ }. \\ ~ \\ fH\theta \text{ }\left( CCl4 \right)\text{ }=\text{ }\text{ }135.5\text{ }kJ\text{ }mol1\text{ }. \\ ~ \\ aH\theta \text{ }\left( C \right)\text{ }=\text{ }715.0\text{ }kJ\text{ }mol1\text{ }, \\ ~ \\ where\text{ }aH\theta \text{ }is\text{ }enthalpy\text{ }of\text{ }atomisation \\ ~ \\ aH\theta \text{ }\left( Cl2 \right)\text{ }=\text{ }242\text{ }kJ\text{ }mol1 \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-183416d42bdde6938df21980fb24335b_l3.png "Rendered by QuickLaTeX.com")
Solution: The synthetic conditions suggesting to the given upsides of enthalpies are:
Solution: The response that happens during the arrangement of CH3OH(l) can be composed as: \[C\left( s \right)\text{ }+\text{ }2H2O\left( g \right)\text{ }+\text{ }\left( 1/2...
![\[N2\text{ }\left( g \right)\text{ }+\text{ }3H2\text{ }\left( g \right)\text{ }\to \text{ }2NH3\text{ }\left( g \right)\text{ };\text{ }rH0=\text{ }\text{ }92.4\text{ }kJ\text{ }mol1\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d81c6dc91c7c744bc321c09dcfa91bab_l3.png "Rendered by QuickLaTeX.com")
Solution: Standard enthalpy of development of a compound is the adjustment of enthalpy that happens during the arrangement of 1 mole of a substance in its standard structure from its constituent...
![\[N2O4\left( g \right)\text{ }+\text{ }3CO\left( g \right)\to \text{ }N2O\left( g \right)\text{ }+\text{ }3\text{ }CO2\left( g \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-84c70293d06a7f15cf0337e2f45f3df8_l3.png "Rendered by QuickLaTeX.com")
Solution: ∆rH for a response is characterized as the contrast between ∆fH worth of items and ∆fH worth of reactants.
(ii) 
(iii) 
(iv) 
Answer: Isoelectronic species have the same number of electrons as one another. i) The elements $F^-$ and $O_2$ each have ten electrons. As a result, they are considered isoelectronic. (ii) The...
Answer: A period's left to right movement reduces atomic radius. Because external electrons are available in a comparable valence shell, the atomic number increases from left to right, increasing...
Solution: Arrangement of CO2 from carbon and dioxygen gas can be addressed as: \[\begin{array}{*{35}{l}} \left( 1\text{ }mole\text{ }=\text{ }44\text{ }g \right) \\ ~ \\ Warmth\text{...
Answer: The atomic radius is the size of an atom. It measures an atom's size. If an element is a metal, its radius is metallic, and if it is not a metal, its radius is covalent. The metallic radius...
Answer: The number of valence electrons in any element determines the chemical and physical properties of that element. When elements in the same group of the periodic table have the same number of...
Answer: (i) Lawrencium (Lr), which has an atomic number of Z=103, and Berkelium (Bk), which has an atomic number of Z=97, are the two elements with the highest atomic numbers. (ii) Seaborgium (Sg),...
Answer: The first phase has two elements, while the second period has eight. As a result, element Z = 11 starts the third phase. The third period currently has eight elements. As a result, the 18th...
Answer: The seventh period of the periodic table contains elements with atomic numbers Z = 87–114. The element with Z = 114 is thus available in the seventh period. In the seventh period, the first...
![\[\begin{array}{*{35}{l}} fusH\text{ }=\text{ }6.03\text{ }kJ\text{ }mol1\text{ }at\text{ }0{}^\circ C. \\ ~ \\ Cp\left[ H2O\left( l \right) \right]\text{ }=\text{ }75.3\text{ }J\text{ }mol1\text{ }K\text{ }\text{ }1 \\ ~ \\ Cp\left[ H2O\left( s \right) \right]\text{ }=\text{ }36.8\text{ }J\text{ }mol1\text{ }K\text{ }\text{ }1 \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ae9ce04526cb31bbc938dd00ac9ef2b9_l3.png "Rendered by QuickLaTeX.com")
Solution: Complete enthalpy change engaged with the change is the amount of the accompanying changes: (a) Energy change engaged with the change of 1 mol of water at 10°C to 1 mol of water at 0°C....
Answer: For the outermost shells of a periodic table, a period shows the value of the main quantum number (n). Each period begins with the primary quantum number (n). And n for the 6th period is 6....
Answer: Mendeleev’s Approach for periodic law Modern approach for the periodic law Periodic functions of the atomic mass of the corresponding elements determine the chemical and physical properties...
Answer: Mendeleev arranged the elements in his periodic table by atomic weight. Mendeleev classified the elements into groups and periods based on atomic weight. Mendeleev grouped elements with...
Answer: It divides items into periods and groups based on their qualities. This method simplifies and organizes the study of elements and their compounds. Elements with similar characteristics are...
solution: From the statement of warmth (q), \[q\text{ }=\text{ }m.\text{ }c.\text{ }T\] Where, \[\begin{array}{*{35}{l}} c\text{ }=\text{ }molar\text{ }warmth\text{ }limit \\ ~ \\...
Answer: Option i) & ii) Lithium exhibits a high ionization enthalpy in addition to a high degree of hydration. This is owing to the fact that it is so little.
Answer: Option i) & ii) Be mimics Al (diagonal relationship), and together they create a protective film of oxide that is resistant to acid assault. Because of the high hydration enthalpy of...
ions (ii) 
ions (iii) 
ions (iv) 
ionsAnswer: Option ii) & iii) Because of this, when zeolite, which is sodium aluminium silicate, reacts with hard water, the sodium ion of zeolite is swapped for calcium and magnesium ions.
![\[NH2CN\left( g \right)\text{ }+\text{ }3/2\text{ }O2\left( g \right)\text{ }\to \text{ }N2\left( g \right)\text{ }+\text{ }CO2\left( g \right)\text{ }+\text{ }H2O\left( l \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-6cb518a194b0305964737ad87e3d7289_l3.png "Rendered by QuickLaTeX.com")
Solution: Enthalpy change for a response (∆H) is given by the articulation, \[H\text{ }=\text{ }U\text{ }+\text{ }ngRT\] Where, \[\begin{array}{*{35}{l}} U\text{ }=\text{ }change\text{...
Answer: Option ii) & iv) Periods begin with alkali metals. For their period, alkali metals have the biggest atomic radius. They have low density due to their huge size and low bulk. Alkali...
Answer: Option iv) Because they are hygroscopic in nature, the calcium, barium, and strontium halides operate as a dehydrating agent in the body. They are capable of absorbing moisture....
solution: As per the principal law of thermodynamics, \[U\text{ }=\text{ }q\text{ }+\text{ }W\text{ }\left( I \right)\] Where, \[\begin{array}{*{35}{l}} U\text{ }=\text{ }change\text{...
Answer: Option i) Slaked lime is formed by combining quicklime and water to form a paste. Because quicklime can be used in the manufacture of cement, slaked lime can be used in the manufacture of...
![\[,\text{ }A\text{ }+\text{ }B\text{ }\to \text{ }C\text{ }+\text{ }D\text{ }+\text{ }q\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f134f882cde1f21a1a7d40a02e8eec6e_l3.png "Rendered by QuickLaTeX.com")
Solution: For a response to be unconstrained, ∆G ought to be negative. \[G\text{ }=\text{ }H\text{ }\text{ }TS\] As indicated by the inquiry, for the given response, ...
Answer: Option iv) The formula for soda ash is $Na_2CO_3$ that is sodium carbonate.
Answer: Option i) When heated, all of the elements, with the exception of beryllium, mix with hydrogen to create their hydrides.
Answer: Option iii) Calcium hydroxide dissociates in an aqueous solution, releasing calcium cations and hydroxide anions. Calcium oxide is the chemical compound known as quicklime. Milk of lime is a...
solution: As indicated by the inquiry, Subsequently, the ideal condition is the one that addresses the development of CH4 (g) i.e., Enthalpy of arrangement of\[~CH4\left( g \right)\text{...
Answer: Option i) When plaster of Paris is heated to 200°C, it transforms into anhydrous calcium sulphate, often known as dead plaster, which lacks setting properties since it absorbs water at a...
Answer: Option ii) The addition of gypsum serves only to slow down the setting process of the cement, allowing it to solidify to a sufficiently hard state before use.
Answer: option i) The concentration of these solvated ions in the sodium in liquid ammonia solution changes the color to copper. So the ammoniated electron is responsible for the solution's color.